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lions [1.4K]
3 years ago
6

When metallic aluminum is added to a solution containing iron(II) sulfate a reaction occurs. What species is being oxidized in t

he overall reaction? Al(s) Fe2+(aq) SO42−(aq) Al3+(aq)
Chemistry
1 answer:
REY [17]3 years ago
4 0

<u>Answer:</u> Aluminium is getting oxidized in the given chemical reaction.

<u>Explanation:</u>

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

2Al(s)+3FeSO_4(aq.)\rightarrow Al_2(SO_4)_3(aq.)+3Fe(s)

The half cell reactions for the above reaction follows:

<u>Oxidation half reaction:</u>  Al\rightarrow Al^{3+}+3e^-

<u>Reduction half reaction:</u>  Fe^{2+}+2e^-\rightarrow Fe

As, aluminium is loosing 3 electrons to form aluminium cation. Thus, it is getting oxidized. Iron is gaining 2 electrons to form iron anion. Thus, it is getting reduced.

Hence, the oxidized species of the given reaction is aluminium.

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Potassium metal is delicate and white with a shimmering shine, has a low melting point, and is a decent channel of heat and electricity.

Explanation:

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3 years ago
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2. Arnie is going to dissolve 2.65g of zinc using 6.0M hydrochloric acid. A) what volume of the acid will he need to dissolve al
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Answer:

Explanation:

Zn + 2HCl = ZnCl₂ + H₂

A ) mole of Zn = 2.65 / 65

= .04 mol

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.08 mol

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B )

volume of gas at NTP :

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= .896 liter

we have to find this volume at given temperature and pressure

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

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C )

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5 0
3 years ago
A large flask is evacuated and weighed, filled with argon gas, and then reweighed. When reweighed, the flask is found to have ga
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Answer:

The molar mass of the unknown gas is 100.4 g/mol

Explanation:

Step 1: Data given

Molar mass of argon = 39.95 g/mol

After filling with argon the flask gained 3.221 grams

After filling with an unknown gas, the flask gained 8.107 grams

Step 2: Calculate the molar mass of the unknown gas

The gas with the higher molar mass will have the higher density.

Ar - 3.224 g; molar mass = 39.95 g/mol

X = 8.102 g; molar mass = ??

Molar mass of the unknown gas = 8.102g X *(39.95 g/mol  / 3.224 g) = 100.4 g/mol

The molar mass of the unknown gas is 100.4 g/mol

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