What enzymes Break it down sugar ???

Chemistry

1 answer:

tatyana61 [14]3 years ago

6 0

Amylase has the process in which it breaks down of sugars when you’re having carbohydrates

You might be interested in

What is the oxidation state magnesium?

erastova [34]

Magnesium is a 2+ metal, located in the alkaline earth metals group of the periodic table (group 2).

8 0

3 years ago

Pleeeeeeeeeeeeeeeeeeas help

SIZIF [17.4K]

Answer:

For young organic materials, the carbon-14 (radiocarbon) method is used. The effective dating range of the carbon-14 method is between 100 and 50,000 years.

Explanation:

The answer is the explanation.

4 0

2 years ago

How many moles of solute are contained in a 250.0 ml solution with a concentration of 2.5 M?

larisa [96]

The unit M means that mole/L, So first change the unit of solution volume to L which is 0.25 L. So the mole of solute is 2.5*0.25=0.625 mol.

7 0

3 years ago

Read 2 more answers

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$