1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Allisa [31]
4 years ago
5

The wavelength of light visible to the human eye is on the order of 5 x 10-7 m. if the speed of light in air is 3 x 108 m/s, fin

d the frequency of the lightwave.
Physics
1 answer:
juin [17]4 years ago
6 0

The frequency of light wave is 0.6*10^15 Hz.

The relation between the speed of light, frequency, and wavelength is given as

c=λν

Plugging the values in the above equation

3*10^8=5*10^(-7)*ν

ν=0.6*10^15 Hz.

Therefore the frequency of the light wave is 0.6*10^15 Hz.

You might be interested in
when you run, your feet are pushing you forward. Friction keeps your foot in contact with the ground. According to Newton's thir
Studentka2010 [4]

Answer:

only you are in motion

Explanation:

it is because the ground causes friction to make you stop but you are the object in motion :)

3 0
3 years ago
A baseball has a mass of 140 grams , traveling at 30 m/s moves a fielders glove backward 35 cm when the ball is caught. What is
Sloan [31]
Since the initial velocity is 30 and the final is 0. 15 is the vave so you can use that with 1/2mv^2 to find the force
8 0
3 years ago
A student constructed a simple electric circuit where two light bulbs were connected in parallel. The circuit power source was a
Natasha2012 [34]

Answer:

RT =  17 ohms

Explanation:

For two parallel resistances in a circuit the combined resistance is given by:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}\\\\\frac{1}{R_T}=\frac{R_2+R_1}{R_1R_2}\\\\R_T=\frac{R_1R_2}{R_1+R_2}

R1 = 25 ohms

R2 = 50 ohms

You replace the values of R1 and R2 in the formula for RT:

R_T=\frac{(25)(50)}{25+50}ohms=16.66\ ohms \approx 17\ ohms

hence, the combined resitances is 17 ohms

5 0
4 years ago
The half-life of radium-224 is approximately 3.66 days. Step 1 of 3 : Determine a so that A(t)=A0at describes the amount of radi
Dafna11 [192]

Answer:

a = 0.827468

Explanation:

given,

half life of radium-224 = 3.66 days

now,

 A(t) = A_0 a^t

t is the time

A₀ is the amount at t = 0

at t = 0 ,    A(0) = 1

A(3.66) = 1/2

at t = 3.66

A(t) = A_0 a^t

\dfrac{1}{2}= 1. a^{3.66}

taking log both side

3.66 log (a) = log (0.5)

       log a = -0.0822

now,a = 10^{-0.0822}

         a = 0.827468

4 0
3 years ago
Potential energy is
katen-ka-za [31]

Answer:

Potential energy is stored energy in a state of readiness.

Explanation:

7 0
3 years ago
Other questions:
  • The sun is 30 degrees above the horizon. it makes a 51 m long shadow of a tall tree. part a how high is the tree?
    11·2 answers
  • A car or truck moving down the highway has what energy by virtue of its motion
    13·1 answer
  • If you're ever standing on a mountaintop when a dark cloud passes overhead and your hair stands up, get off the mountain fast. H
    15·1 answer
  • What causes sedimentary rock to change into metamorphic rock? A) cooling B) melting C) heat and pressure D) weathering and erosi
    10·2 answers
  • Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak
    7·1 answer
  • A force F₁ of magnitude 6.50 units acts at the origin in a direction 49.0° above the positive x axis. A second force F₂ of magni
    6·1 answer
  • If a person was interested how light passes through clear substances, what field of science would be the best course of study?
    12·1 answer
  • Mechanical (sound) waves to Earth from satellites. How is this possible? aves are unable to travel through a vacuum, such as thr
    8·1 answer
  • Both mechanical and electromagnetic waves _____. have compressions and rarefactions oscillate in the same direction as the wave
    7·1 answer
  • Help me please
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!