You take the mass number and subtract the number of neutrons
Answer:
Volume=0.003m^3 density=6000kg/m^3
Explanation:
mass=18kg
volume=length x width x height
Volume of block=0.1x0.15x0.2
volume of block=0.003m^3
Density=mass ➗ volume
Density=18 ➗ 0.003
Density=6000kg/m^3
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).
If we call
![v_p](https://tex.z-dn.net/?f=v_p)
the speed of the primary waves and
![v_s](https://tex.z-dn.net/?f=v_s)
the speed of the secondary waves, and we call
![S](https://tex.z-dn.net/?f=S)
the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as
![t_P = \frac{S}{v_P}](https://tex.z-dn.net/?f=t_P%20%3D%20%20%5Cfrac%7BS%7D%7Bv_P%7D%20)
![t_S= \frac{S}{v_S}](https://tex.z-dn.net/?f=t_S%3D%20%5Cfrac%7BS%7D%7Bv_S%7D%20)
So the lag time between the arrival of the P-waves and of the S-waves is
![\Delta t = t_S-t_P= \frac{S}{v_S}- \frac{S}{v_P}= S(\frac{1}{v_S}- \frac{1}{v_P})](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20t_S-t_P%3D%20%5Cfrac%7BS%7D%7Bv_S%7D-%20%5Cfrac%7BS%7D%7Bv_P%7D%3D%20S%28%5Cfrac%7B1%7D%7Bv_S%7D-%20%5Cfrac%7B1%7D%7Bv_P%7D%29%20%20%20%20)
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
The Correct answer to this question for Penn Foster Students is: Direction
In that formula for Energy, 'F' is the frequency of the photon.
But <u>Frequency = (speed)/(wavelength)</u>, so we can write the
Energy formula as
E = h c / (wavelength) .
So the energy, in joules, of a photon with that wavelength, is . . .
E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)
= <em>(1.989 x 10⁻²⁵) / (that wavelength, in meters) .</em>