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Keith_Richards [23]
3 years ago
10

The problem faced by Galloping Gertie, the failed bridge across the Tacoma Narrows, was caused because the engineers did not fol

low the perform tests on the prototype/testing/ step in the engineering design process.
Engineering
1 answer:
Allushta [10]3 years ago
7 0

Answer:

1) Perform

2) Prototype

Explanation:

The prototype testing phase of the design process to test the readiness of the design for the intended use

The prototype which is a first or early model of the project made so as to ensure proper functioning of the concept is to pass through general function test as well as design performance evaluation in a testing or lab setting

Other tests include, excessive stress test, testing to failure and other design tests.

Therefore;

The problem faced by Galloping Gertie the failed bridge across the Tacoma Narrows, was caused because the engineers did not perform tests on the prototype in the engineering design process.

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Assuming the point estimate in Problem 6.36 is the true population parameter, what is the probability that a particular assay, w
sp2606 [1]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability is 0.958

Explanation:

The explanation is shown on the second and third uploaded image

3 0
3 years ago
Air-conditioners consume a significant amount of electrical energy in buildings. Split air conditioner is a unitary system where
nydimaria [60]

Answer:

Evaporator,Compressor,Condensor ,Expanding valve

Explanation:

Split air conditioning :

  Split air conditioning means that, condensor unit or some time called outdoor unit is split from evaporator.It means that evaporator and condensor are placed at some distance.

The four component of split air conditioning system are as follows

1.Evaporator

 It absorb heat from room and produces the cooling effect.

2.Compressor

 It compresses the refrigerant which exits from evaporator.

3.Condensor

 It rejects the heat and cool the evaporator.

4.Expanding valve

  It allows to refrigerant to cool up to evaporator pressure.

6 0
3 years ago
Design a 7.5-V zener regulator circuit using a 7.5-V zener specified at 10mA. The zener has an incremental resistance of rZ = 30
hram777 [196]

Answer:

The answer is given in the explanation.

Explanation:

The circuit is as indicated in the attached figure.

From the analytical description the zener voltage is given as

V_z=V_z_o+I_zr_z

Here

Vzo is the voltage at which the slope of 1/rz intersects the voltage axis it is equal to knee voltage.

The equivalent model is shown in the attached figure.

From the above equation, Vzo is calculated as

V_z_o=V_z-I_zr_z

Here Vz is given as 7.5 V

Iz is given as 10 mA

rz is given as 30 Ω

Thus the Vzo is given as

V_z_o=V_z-I_zr_z\\V_z_o=7.4-30*10*10^{-3}\\V_z_o=7.5-0.3\\V_z_o=7.2 V

The value of I_L is given as 5 mA

Now the expression of current is as

I=I_z+I_L\\I=10mA+5mA\\I=15 mA

Now the resistance is calculated as

R=\dfrac{V-Vo}{I}\\R=\dfrac{10-7.2}{15*10^{-3}}\\R=186.66

So the value of resistance is 186.66 Ω.

Considering the supply voltage is increased by 10%

V is 10-10%*10=10+1=11 so the

R=\dfrac{V-Vo}{I}\\186.66=\dfrac{11-V_o}{15*10^{-3}}\\V_o=8.2 V

Considering the supply voltage is decreased by 10%

V is 10-10%*10=10-1=9 so the

R=\dfrac{V-Vo}{I}\\186.66=\dfrac{9-V_o}{15*10^{-3}}\\V_o=6.2 V

Now if the supply voltage is 10% high and the value of Load is removed i.e I=Iz only which is 10mA

so

R=\dfrac{V-Vo}{I'}\\186.66=\dfrac{11-V_o}{10*10^{-3}}\\V_o=9.13 V

Now the largest load current thus that the supply voltage is 10% low and the current of zener is knee current thus

V_z_o=V_z-I_zr_z\\V_z_o=7.5-30*0.5*10^{-3}\\V_z_o=7.5-0.015\\V_z_o=7.485 V

R=\dfrac{V-Vo}{I'}\\186.66=\dfrac{9-7.485}{I}\\I=10.71 mA

The load voltage is 7.485 V

8 0
2 years ago
A wood pole with a diameter of 10 in. has a moisture content of 5%. The fiber saturation point (FSP) for this wood is 30%. The w
Mekhanik [1.2K]

Answer:

a) Δd(change in wood diameter) = 5%

b) The wood would swell since the moisture content is increasing which will also led to increase in the wood's diameter

C) new diameter (D2) = 10.5 in

Explanation:

Wood pole diameter = 10 inches

moisture content = 5%

FSP = 30%

A) The percentage change in the wood's diameter

note : moisture fluctuations from 5% to 30% causes dimensional changes in the wood but above 30% up to 55% causes no change. hence this formula can be used to calculate percentage change in the wood's diameter

Δd/d = 1/5(30 - 5)

Δd/d = 5%  

Δd = 5%

B) would the wood swell or shrink

The wood would swell since the moisture content is increasing which will also led to increase in the wood's diameter

C) The new diameter of the wood

D2 = D + D( \frac{M1}{100} )

D = initial diameter= 10 in , M1 = initial moisture content = 5%

therefore D2 = 10 + 10( 5/100 )

new diameter (D2) = 10.5 in

5 0
2 years ago
An airliner is flying at 34,000 ft cruise altitude on a standard day. Calculate the pressure difference between the cabin and th
nadya68 [22]

Answer:

\Delta P=61,952.8\ lb/ft^2

Explanation:

Given

Airline flying at 34,000 ft.

Cabin pressurized to an altitude 8,000 ft.

We know that at standard condition ,density of air

\rho =0.074\ lb/ft^3

We know that pressure difference    

ΔP=ρ g ΔZ

Here ΔZ=34,000-8,000  ft

        ΔZ=26,000 ft

g= 32.2\ ft/s^2

ΔP=0.074 x 32.2 x 26,000

\Delta P=61,952.8\ lb/ft^2

So pressure difference will be \Delta P=61,952.8\ lb/ft^2.

7 0
3 years ago
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