A resonant six-turn loop of closely spaced turns is operating at 50 MHz. The radius of the loop is λ/30, and the loop is connect
ed to a 50-ohm transmission line. The radius of the wire is λ/300, its conductivity is σ = 5.7 × 107 S/m, and the spacing between the turns is λ/100. Determine the:
a. the directivity of the antenna (in dB)
b. radiation efficiency taking into account the proximity effects of the turns
c. reflection efficiency gain of the antenna (in dB)
a. the directivity of the antenna (in dB)
b. radiation efficiency taking into account the proximity effects of the turns
c. reflection efficiency gain of the antenna (in dB)
1 answer:
You might be interested in
Answer:
the surface heat-transfer coefficient due to natural convection during the initial cooling period. = 4.93 w/m²k
Explanation:
check attachement for answer explanation
Answer:
Explanation:
Given that :
The initial volume of water = 1000.00 mL = 1000000 mm³
The initial temperature of the water = 10° C
The height of the water column h = 1000.00 mm
The final temperature of the water = 70° C
The coefficient of thermal expansion for the glass is ∝ =
The objective is to determine the the depth of the water column
In order to do that we will need to determine the volume of the water.
We obtain the data for physical properties of water at standard sea level atmospheric from pressure tables; So:
At temperature the density of the water is
At temperature the density of the water is
The mass of the water is
Thus; we can say ;
⇒
Thus, the volume of the water after heating to a required temperature of is 1022400 mm³
However; taking an integral look at this process; the volume of the water before heating can be deduced by the relation:
The area of the water before heating is:
The area of the heated water is :
Finally, the depth of the heated hot water is:
Hence the depth of the heated hot water is