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My name is Ann [436]
3 years ago
15

A resonant six-turn loop of closely spaced turns is operating at 50 MHz. The radius of the loop is λ/30, and the loop is connect

ed to a 50-ohm transmission line. The radius of the wire is λ/300, its conductivity is σ = 5.7 × 107 S/m, and the spacing between the turns is λ/100. Determine the:
a. the directivity of the antenna (in dB)
b. radiation efficiency taking into account the proximity effects of the turns
c. reflection efficiency gain of the antenna (in dB)

Engineering
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

a) the directivity of the antenna is evaluated to be = 1.761db

b) radiation efficiency is evaluated to be  = 98.67%

c) reflection efficiency gain is evaluated to be =  68%

Explanation:

kindly check the attachment for step to step explanations for better understanding.

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Smothering in this context involves adding a solution like carbon dioxide (CO2) into the fire, this results in a reduction of oxygen in the atmosphere surrounding the class D fire.

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Explanation:

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Steam enters an adiabatic turbine at 10MPa and 500 C and leaves at 10 kPa with a quality of 90%. Neglecting the changes in kinet
Amanda [17]

Answer:

flow ( m ) = 4.852 kg/s

Explanation:

Given:

- Inlet of Turbine

        P_1 = 10 MPa

        T_1 = 500 C

- Outlet of Turbine

        P_2 = 10 KPa

        x = 0.9

- Power output of Turbine W_out = 5 MW

Find:

Determine the mass ow rate required

Solution:

- Use steam Table A.4 to determine specific enthalpy for inlet conditions:

          P_1 = 10 MPa

          T_1 = 500 C            ---------- > h_1 = 3375.1 KJ/kg

- Use steam Table A.6 to determine specific enthalpy for outlet conditions:

          P_2 = 10 KPa       -------------> h_f = 191.81 KJ/kg

          x = 0.9                  -------------> h_fg = 2392.1 KJ/kg

          h_2 = h_f + x*h_fg

          h_2 = 191.81 + 0.9*2392.1 = 2344.7 KJ/kg

- The work produced by the turbine W_out is given by first Law of thermodynamics:

          W_out = flow(m) * ( h_1 - h_2 )

          flow ( m ) = W_out / ( h_1 - h_2 )

- Plug in values:

          flow ( m ) = 5*10^3 / ( 3375.1 - 2344.7 )

          flow ( m ) = 4.852 kg/s

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3 years ago
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