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borishaifa [10]
3 years ago
5

g Asbestos is a fibrous silicate mineral with remarkably high tensile strength. But is no longer used because airborne asbestos

particles can cause lung cancer. Grunerite, a type of asbestos, has a tensile strength of 3.5 × 10ଶ kg mmଶ ⁄ (meaning a strand of grunerite with a 1-mmଶ cross-sectional area can hold up to 3.5 × 10ଶ kg). The tensile strength of aluminum and Steel No. 5137 are 2.4 × 10ସ lb inଶ ⁄ and 5.0 × 10ସ lb inଶ ⁄ respectively. Calculate the cross section areas in mmଶ of wires of aluminum and of Steel No. 5137 that have the same tensile strength as a fiber of grunerite with a cross-sectional area of 1.0 μmଶ
Engineering
1 answer:
otez555 [7]3 years ago
8 0

Answer:

Aluminum cross sectional area = 1.99 * 10^-5 mm^2

Steel cross sectional area = 9.95* 10^-6 mm^2

Explanation:

Given data:

Tensile strength of Grunerite = 3.5 * 10^2 kg/mm^2 = 3.5 * 10^-4 kg/<em>u</em>m^2

Tensile strength of Aluminum = 2.5 × 10^4 lb/in2 =  2.5 × 10^4 * 703.07 kg/m^2

Tensile strength of Steel number 5137 = 5.0 × 10^4 lb/in2 = 5.0 × 10^4*703.07 kg/m^2

<u>Calculating the cross sectional area of the wires of aluminum and steel No5137</u>

first we will determine the cross sectional area of the aluminum wire ( A ) by equating tensile strength of aluminum with the tensile strength

of Grunerite

(2.5 × 10^4 * 703.07)  * A = 3.5 * 10^-4 kg

Hence ; A = 1.99 * 10^-5 mm^2

Next we calculate the cross sectional area of steel

5.0 × 10^4*703.07 kg/m^2 * A" = 3.5 * 10^-4 kg

Hence ; A" = 9.95* 10^-6 mm^2

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what advantage might there be to having the encoder located on the motor side of the gearhead instead of at the output shaft of
UkoKoshka [18]

Answer:

The definition is defined in the clarification segment following the table, as per the particular circumstance.

Explanation:

  • In something like a closed-loop device, shaft encoders were being used, the output of which could be influenced either by encoder location. Most motors have been used for gearbox speed reduction (RPM). Assume there's also a gearbox reduction of 30:1 as well as the motor is already spinning at a higher 3000 rpm, then the outcome feature shaft speed would be 100 rpm.
  • This suggests that every other output shaft turning correlates to 30 input shaft flips, and even if the encoder contains 40 holes through its diameter, instead every output shaft revolution contributes to 40\times 30=1200 pulses. That implies an accuracy of 0.3 degrees of rotation of the final output shaft (\frac{360 \ degree}{1200} =0.3).  

Accuracy as well as reliability are thus given by positioning the encoder on the engine side instead of on the outcome shaft including its gear head.

6 0
3 years ago
A cable in a motor hoist must lift a 700-lb engine. The steel cable is 0.375in. in diameter. What is the stress in the cable?
UkoKoshka [18]

Answer:43.70 MPa

Explanation:

Given

mass of engine 700 lb \approx 317.515 kg

diameter of cable 0.375 in.\approx 9.525 mm

A=\frac{\pi d^2}{4}=71.26 mm^2

we know stress(\sigma)=\frac{load\ applied}{area\ of\ cross-section}

\sigma =\frac{317.515\times 9.81}{71.26\times 10^{-6}}=43.70 MPa

7 0
4 years ago
What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 5
viva [34]

The approximate average power output is mathematically given as

P=1097.6w

<h3>What is the approximate average power output?</h3>

Question Parameters:

Iowa with a 10 m2 swept area and 50 m hub height

Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

Generally, the equation for the average output power  is mathematically given as

P=0.5 \phi BAu^3*n\\

Where

B= Benz coefficient

n=0.8

Therefore

P=0.5*1*0.8*10*7^3*0.8

P=1097.6w

For more information on Power

brainly.com/question/10203153

Complete Question

What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 50 m hub height? Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

7 0
2 years ago
The roof of a refrigerated truck compartment consists of a layer of foamed urethane insulation (t2 = 21 mm, ki = 0.026 W/m K) be
lakkis [162]

Answer:

Tso = 28.15°C

Explanation:

given data

t2 = 21 mm

ki = 0.026 W/m K

t1 = 9 mm

kp = 180 W/m K

length of the roof is L = 13 m

net solar radiation into the roof = 107 W/m²

temperature of the inner surface Ts,i = -4°C

air temperature is T[infinity] = 29°C

convective heat transfer coefficient h = 47 W/m² K

solution

As when energy on the outer surface at roof of a refrigerated truck that is balance as

Q = \frac{T \infty - T si }{\frac{1}{hA}+\frac{t1}{AKp}+\frac{t2}{AKi}+\frac{t1}{aKp}}       .....................1

Q = \frac{T \infty - Tso}{\frac{1}{hA}}                         .....................2

now we compare both equation 1 and 2 and put here value

\frac{29-(-4)}{\frac{1}{47}+\frac{2\times0.009}{180}+\frac{0.021}{0.026}} = \frac{29-Tso}{\frac{1}{47}}            

solve it and we get

Tso = 28.153113

so Tso = 28.15°C

3 0
3 years ago
5. If you designed a part with an overall width dimension of 1.250 inches and printed it on the same 3D printer using the same f
sleet_krkn [62]

Answer:

hu22 54=52222222222222

3 0
3 years ago
Read 2 more answers
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