Answer:
29.4 N/m
0.1
Explanation:
a) From the restoring Force we know that :
F_r = —k*x
the gravitational force :
F_g=mg
Where:
F_r is the restoring force .
F_g is the gravitational force
g is the acceleration of gravity
k is the constant force
xi , x2 are the displacement made by the two masses.
Givens:
<em>m1 = 1.29 kg</em>
<em>m2 = 0.3 kg </em>
<em>x1 = -0.75 m </em>
<em>x2 = -0.2 m </em>
<em>g = 9.8 m/s^2 </em>
Plugging known information to get :
F_r =F_g
-k*x1 + k*x2=m1*g-m2*g
k=29.4 N/m
b) To get the unloaded length 1:
l=x1-(F_1/k)
Givens:
m1 = 1.95kg , x1 = —0.75m
Plugging known infromation to get :
l= x1 — (F_1/k)
= 0.1
Answer:by book 2 do you mean the original or re, if you you mean who taught kaneki to control his kagune it was yoshimura (the manager) but if your talking about how to fight with control of his kagune its was Yomo
Explanation: if I'm wrong correct me and i'll do more research
Answer:
Potential
Explanation:
The most accurate term is Electrostatic potential energy
It's named like this because the force between charges or electrons is called electrostatic force .
Answer:
Explanation:
Calories to be burnt = 3500 - 2500 = 1000 Cals .
Efficiency of conversion to mechanical work is 25 % .
Work needed to burn this much of Cals = 1000 x 100 / 25 = 4000 Cals.
4000 Cals = 4.2 x 4000 = 16800 J .
Work done in one jump = kinetic energy while jumping
= 1/2 m v²
= .5 x 70 x 3.3²
= 381.15 J .
Number of jumps required = 16800 / 381.15
= 44 .
Answer:
20.5s
Explanation:
Given parameters:
Distance = 30m
Unknown:
Time = ?
Solution:
The time it will take to hop a distance of 30m using the speed for the 5m trial is the duration of the trip.
The speed for the 5m trial = 1.46m/s
Now;
Speed = 
Distance = speed x time
time = 
Input the parameters and solve;
time = 
= 20.5s
