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joja [24]
3 years ago
15

What is the magnification when an object is placed at 2f from the pole of the convex mirror? 

Physics
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

Linear magnification = 1/3

Explanation:

Given:

Convex mirror

Object's distance from pole = 2f

Find:

Linear magnification

Computation:

Object distance, u = −2f

So,

1/v + 1/u = 1/f

1/v + 1/(-2f) = 1/f

1/v = 1/f + 1/2f

BY taking LCM

1/v = 3 / 2f

v = 2f / 3

Magnification, M = -v / u

So,

Magnification, M = (2f / 3) / 2f

Magnification, M = 2f / 6f

Magnification, M = 2 / 6

Linear magnification = 1/3

 

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Two molecules of lithium are combined with 225 grams of bromine to form two molecules of lithium bromide. If you end up with 690
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The amount of Li present to start the reaction is 55.18g

<u>Explanation:</u>

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Molecular weight of Br₂ = 159.808 g/mol

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Moles of Br₂ present during the reaction = 225 / 159.808

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Molecular weight of LiBr = 86.845 g/mol

Mass of LiBr formed = 690 g

moles of LiBr produced = 690 / 86.845

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According to the balanced equation, 2 molecules of Li reacts to for 2 molecule of LiBr

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The molecular weight of Li is 6.941 g/mol

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