What is the magnetic flux linkage, in units of Weber, for a coil of 360 turns and cross sectional area of 0.133 m^2 when the mag
netic flux density of 1.74 T passes through the area perpendicularly?
1 answer:
Answer:
83.3 Wb
Explanation:
The magnetic flux linkage through the coil is given by:
where
B is the magnetic field strength
A is the cross sectional area
N is the number of turns in the coil
is the angle between the direction of the field and the normal to the coil
In this problem:
B = 1.74 T
A = 0.133 m^2
N = 360
Therefore, the magnetic flux linkage is
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