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Kaylis [27]
3 years ago
8

Let's say that we have a pilot that is dropping a package from a plane that is flying horizontally at a constant speed. If we ne

glect air resistance when the package hits the ground what would be the horizontal location of the package with respect to the plane?
Physics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

The package will be directly below the location of the plane.

Explanation:

Look up projectile motion for more information. The horizontal speed of the package is separate from the vertical speed of the package. The vertical speed of the falling package will be based on the rate of acceleration and the height of the package when dropped. The horizontal speed of the package will be the same as the plane so the package will remain directly below the plane the entire time until the package hits the ground.

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Two identical circular, wire loops 35.0 cm in diameter each carry a current of 2.80 A in the same direction. These loops are par
defon

Answer:

The answer is "4659.2 \times 10^{-24} \ N"

Explanation:

The magnetic field at ehe mid point of the coils is,

\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\

Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.

\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\

       =\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{  1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\

Calculating the force experienced through the protons:

F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N

7 0
3 years ago
Answer all of these questions and you will get the brainlist
Gnoma [55]

Answer:

2 ans : the bell has 8550 J energy

5 0
3 years ago
Read 2 more answers
What is the kinetic energy of a 1200 kg roller coaster that is moving with a speed of 24.0 m/s. ?
Vanyuwa [196]

Answer: 345600 J

Explanation: solution attached

KE= 1/2 mv²

3 0
3 years ago
Start from 0 m/s and accelerate at 2m/s? Calculate the speed in m/s after acceleration for 5 seconds.
valentinak56 [21]

Answer:

10m/s

Explanation:

2m/s  x  5s=10m/s

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3 years ago
Dos cargas iguales de 10^-7C estan separadas por una distancia de 2m. calcule la fuerza con que se repelen
m_a_m_a [10]

Answer:

F=2.25\times 10^{-5}\ N

Explanation:

According to question,

Charge 1 and charge 2 are 10^{-7}\ C

The distance between charges is 2 m

We need to find the force with which two positive charges repel. It is called electrostatic force of repulsion. It can be given by :

F=\dfrac{kq^2}{r^2}\\\\F=\dfrac{9\times 10^9\times (10^{-7})^2}{2^2}\\\\F=2.25\times 10^{-5}\ N

So, the electric force of repulsion is 2.25\times 10^{-5}\ N.

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3 years ago
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