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WARRIOR [948]
3 years ago
11

You notice the flagpole at school vibrating in the breeze. You count the vibrations and find that

Physics
1 answer:
Lelu [443]3 years ago
6 0

Answer: 12.5m

Explanation:

Given the following :

Flagpole makes 20 complete vibrations in 10 seconds

Velocity (V) of vibration = 25m/s

Find the wavelength of vibration (λ) =?

Frequency is number of complete oscillation per Second

Therefore ;

Frequency (F) = number of oscillations / time taken

F = 20 / 10 = 2Hz

Wavelength = Velocity / frequency

Wavelength = 25 / 2

Wavelength = 12.5m

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Refraction occurs when light passing from one medium to another. True or False
kodGreya [7K]

Answer: True

Refraction is a phenomenon in which the light bends or changes its direction (and changes the speed of propagation, as well) <u>when passing through a medium</u> with a refractive index n <u>different from the other medium.  </u>

Where the Refractive index is a number that describes how fast light propagates through a medium or material:

n=\frac{c}{v}

Being n a relation between the speed of light in vacuum c  and its speed in the other medium v .

It is important to note that in this process, the wavelength may be modified because it depends on the medium, however, the refracted ray of light does not change its frequency.

7 0
4 years ago
During a tug-of-war, team A pulls on team B by applying a force of 1390 N to the rope between them. How much work does team A do
butalik [34]

Answer:

5115.2 J

Explanation:

Work: This can be defined as product of force and distance. The S.I unit of work is Joules (J).

From the question,

The expression for work is given as

W = F×d................. Equation 1

Where W = Work done by team A, F = Force applied by team A, d = distance moved by team B.

Given: F = 1390 N, d = 3.68 m

Substitute into equation 1

W = 1390×3.68

W = 5115.2 J.

Hence the work done by team A in pulling team B = 5115.2 J

7 0
4 years ago
What is the velocity of a plane that took 2 hours to travel 1000 miles north?
professor190 [17]
D mid Univisionhdjfjfjfnfjzkakaozkdmxifjfifnfjcifjdnsnsn
3 0
3 years ago
What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use
marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force F_{1}=18\ N

Force F_{2}=26\ N

Force F_{3}=14\ N

We need to calculate the torque due to force F₁

Using formula of torque

\tau_{1}=-F_{1}d_{1}

\tau_{1}=-F_{1}\times\dfrac{a}{2}

Put the value into the formula

\tau_{1}=-18\times\dfrac{0.2}{2}

\tau_{1}=-1.8\ N-m

We need to calculate the torque due to force F₂

Using formula of torque

\tau_{2}=F_{2}d_{2}

\tau_{2}=F_{2}\times\dfrac{a}{2}

Put the value into the formula

\tau_{2}=26\times\dfrac{0.2}{2}

\tau_{2}=2.6\ N-m

We need to calculate the torque due to force F₃

Using formula of torque

\tau_{3}=F_{3}d_{3}

\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}

Put the value into the formula

\tau_{3}=0.1(14\sin45+14\cos45)

\tau_{3}=1.92\ N-m

We need to calculate the net torque on the square plate

\tau=\tau_{1}+\tau_{2}+\tau_{3}

\tau=-1.8+2.6+1.92

\tau=2.72\ N-m

Hence, The net torque on the square plate is 2.72 N-m.

3 0
3 years ago
Observe the figure below. The dashed red line with diamond symbols represents the monthly mean values, centered on the middle of
ddd [48]
You are correct in your thinking 
hope this helps
6 0
3 years ago
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