Answer:
0.56 liters
Explanation:
First we <u>convert 0.80 grams of O₂ into moles</u>, using its molar mass:
- 0.80 g ÷ 32 g/mol = 0.025 mol
At STP, 1 mol of any given mass occupies 22.4 L. With that information in mind we <u>calculate the volume that 0.025 moles of O₂ gas would occupy</u>:
- 0.025 mol * 22.4 L/mol = 0.56 L
Thus the answer is 0.56 liters.
2.47 moles are produce if 85g of N2 react with 180g of Mg
Answer: The percent yield of the reaction is 77.0 %
Explanation:
According to stoichiometry:
2 moles of produces = 2 moles of
2.18 moles of is produced by= of
Mass of =
percent yield =