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Rina8888 [55]
3 years ago
14

A child uses a force of 45 N to pull a sled with a rope. The angle between the rope and the ground is 35 degrees. What is the ho

rizontal component of the tension?
A. 25.8 N
B. 36.9 N
C. 54.9 N
D. 78.5 N
Physics
2 answers:
artcher [175]3 years ago
6 0

Answer:

B

Explanation:

Use trigonometry.

Fₓ = F cos θ

Fₓ = 45 N cos 35°

Fₓ = 36.9 N

Gwar [14]3 years ago
5 0

The correct answer is B) 36.9 N i took the test and got it correct

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When two oppositely charged electrodes are immersed in a solution, positively charged ions are attracted to the negative electro
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conductivity of solution is reduced.

Explanation:

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Due to the process mentioned above , the negatively charged ions are accumulated at the positive electrode and the positively charged ions are accumulated at the negative electrode . This accumulation prevents further attraction of ions at oppositely charged electrodes because the incoming ions face repulsion from already accumulated ions at electrodes.  Further , it creates an emf acting in opposite direction . It reduces the current through the solution. Hence conductivity of solution is reduced.

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3 years ago
A 70 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m . What is the effective spring
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Answer:

29856.521 N/m

Explanation:

m=Mass\ of\ diver=70\ kg\\x=Length\ compressed\ by\ spring=2.3\times 10^{-2}\ m\\a=Acceleration\ due\ to\ gravity=9.81\ m/s^2\\F=Force\ exerted\ by\ diver=m\times a\\\Rightarrow F=70\times 9.81\\\Rightarrow F=686.7\ N\\k=spring\ constant\\F=k\times x\\\Rightarrow k=\frac {F}{x}\\\Rightarrow k=\frac {686.7}{2.3\times 10^{-2}}\\\therefore k=29856.521\ N/m

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3 years ago
The Millersburg Ferry (m = 13000.0 kg loaded) is travelling at 11 m/s when the engines are put in reverse. The engineproduces a
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Explanation:

It is given that,

Mass of Millersburg Ferry, m = 13000 kg

Velocity, v = 11 m/s

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Time period, t = 20 seconds

(a) Impulse is given by the product of force and time taken i.e.

J=F.\Delta t

J=10^6\ N\times 20\ s

J=2\times 10^7\ N-s

(b) Impulse is also given by the change in momentum i.e.

J=\Delta p=p_f-p_i

J=p_f-p_i

p_f=J+p_i

p_f=2\times 10^7\ N-s+13000\ kg\times 11\ m/s

p_f=20143000\ kg-m/s

(c) For new velocity,

v_f=\dfrac{p_f}{m}

v_f=\dfrac{20143000\ kg-m/s}{13000\ kg}

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Hence, this is the required solution.

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