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Ierofanga [76]
3 years ago
11

Two stereoisomers are obtained from the reaction of cyclopentene oxide with dimethylamine. the r,r-isomer is used in the manufac

ture of eclanamine, an antidepressant. what other isomer is obtained?

Chemistry
1 answer:
-Dominant- [34]3 years ago
5 0
I have attached an image that shows the reaction and each isomer formed.

The oxygen of the epoxide adds syn to the alkene, which means the oxygen is on one face of the molecule. Therefore, the epoxide has 2 chiral centers. The dimethyl amine is a nucleophile and it attack a carbon bound to oxygen in an sn2 fashion. This causes the epoxide ring to open, and after a proton transfer, the molecule now has a dimethyl amino group and an adjacent hydroxy group in an anti-relationship. The amine is able to attack either of the two carbons bound to the oxygen in the epoxide and this leads to two isomers. The isomers formed are a pair of enantiomers with the stereochemistry (<em>R,R</em>) and (<em>S,S</em>). Therefore, the second isomer that the question asks for is the (<em>S,S</em>) product shown.

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All food chain in an ecosystem that are connected to each other forms a food web....

Therefore the answer is food web

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Describe the relationship between volume and temperature of an ideal gas
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Answer:

Explanation:

Here, we want to describe the relationship between the volume and temperature of an ideal gas

This relationship is defined by Charles' law

From this law, we know that the volume of a given mass of gas is directly proportional to its temperature at a fixed pressure

What this means is that as long as the pressure remains unchanged, when the volume increases, the temperature increases, and when the volume decreases, the temperature decreases

These can be represented by the mathematical formula below:

\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}

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2 years ago
For the reaction where Δn=−1Δn=−1 , what happens after in increase in volume? ????KQ&gt;K so the reaction shifts toward reactant
Alex787 [66]

Answer:

Explanation:

In general, an increase in pressure (decrease in volume) favors the net reaction  that decreases the total number of moles of gases, and a decrease in pressure (increase in volume) favors the net reaction that increases  the total number of moles of gases.

Δn= b - a

Δn=  moles of gaseous products - moles of gaseous reactants

Therefore, <u>after the increase in volume</u>:

  • If Δn= −1 ⇒ there are more moles of gaseous reactants than gaseous products. The equilibrium will be shifted towards the products, that is, from left to right, and K>Q.
  • If Δn= 0 ⇒ there is the same amount of gaseous moles, both in products and reactants. The system is at equilibrium and K=Q.
  • Δn= +1 ⇒ there are more moles of gaseous products than gaseous reactants. The equilibrium will be shifted towards the reactants, that is, from right to left, and K<Q.

8 0
2 years ago
Chlorine pentafluoride gas is collected at -17.0 °C in an evacuated flask with measured volume of 35.0 L. When all the gas has b
Svet_ta [14]

Answer:

1. The mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of Chlorine pentafluoride, ClF5, is 0.3mole

Explanation:

1. To solve the mass of Chlorine pentafluoride, ClF5, first, let us calculate the molar mass of ClF5. This is illustrated below:

Molar Mass of ClF5 = 35.5 + (5 x 19) = 35.5 + 95 = 130.5g/mol

From the ideal gas equation:

PV = nRT (1)

Recall:

Number of mole(n) = mass (m) /Molar Mass(M)

n = m/M

Now substituting the value of n in equation 1, we have:

PV = nRT

PV = mRT/M

Now we can obtain the mass of Chlorine pentafluoride ClF5 as follow:

Data obtained from the question include:

T (temperature) = -17.0 °C = - 17 + 273 = 256K

V (volume) = 35L

P (pressure) = 0.180 atm

R (gas constant) = 0.082atm.L/Kmol

m (mass of Chlorine pentafluoride) =?

M (molar mass of Chlorine pentafluoride) = 130.5g/mol

PV = mRT/M

0.180 x 35 = m x 0.082 x 256/ 130.5

Cross multiply to express in linear form as shown below:

m x 0.082 x 256 = 0.180x35x130.5

Divide both side by 0.082 x 256

m = (0.180x35x130.5) /(0.082x256)

m = 39.16g

Therefore, the mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of ClF5 can be obtained as follow:

Mass of ClF5 = 39.16g

Molar Mass of ClF5 = 130.5g/mol

Mole of ClF5 =?

Number of mole = Mass /Molar Mass

Mole of ClF5 = 39.16/130.5g

Mole of ClF5 = 0.3mole

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3 years ago
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