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Sholpan [36]
3 years ago
6

Please HURRYYYYYYYYYY

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
6 0
The periodic table is divided into 18 group. A group refers to a column of elements in the periodic table. All the elements in the same group share the same chemical and physical properties. Some of the groups are given specific names while the rest are identified by the first element in that group. The groups with specific names are as follows:
Group 1: Alkali metals
Group 2: Alkali earth metals
Group 11: Coinage metals
Group 15: Pnictogen
Group 16: Chalcogens
Group 17: Halogens
Group 18: Noble gases.

tia_tia [17]3 years ago
4 0
Elements of section s: are those elements whose valence shells are s¹ or s².

This section includes group 1 and 2.

Group 1: Alkalyne metals (Li, Na, K, Rb, Cs, Fr): react violently with water.

Group 2. Alkalyne earth metals (Be, Mg, Ca, Sr, Ba, Ra: react less violently with water.

Elements of both group 1 and group 2 shine, are conductive and are malleable and ductile.

Elements of section p: are those elements whose valence shells are p¹, or p², or p³, or p⁴, or p⁵, or p⁶.

This section includes the groups 13, 14, 15, 16, 17 and 18.

Most of those elements and non-metals except for B, Si, Ge, As, Sb, Te and Po which are metalloids (they have some characteristics of metals and some characteristics of non-metal).

Non metals are brittle and poor conductive.

Elements of section d is the biggest group. These are transition metals. In this group the electrons fill the type d orbitals.

This section includes groups 3 through 12.

The properties of these elements are those of metals: high conductivitiy, mallability and electrical conductivity.

Elements of section f are other transition metals (inner transition metals). They partially fill some f orbitals.
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Answer:

The K_{m} of a substrate will be "10 μM".

Explanation:

The given values are:

E_{t} = 20 \ nM

[Substract] = 40 \ \mu M

K_{cat}=600 \ s^{-1}

Reaction velocity, Vo=9.6 \ \mu M s^{-1}

As we know,

⇒  Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}

On putting the estimated values, we get

⇒  9.6=\frac{600\times 20\times 10^{-3}\times 40}{K_{m}+40}

⇒  K_{m}+40=\frac{600\times 20\times 10^{-3}\times 40}{9.6}

⇒  K_{m}+40=50

On subtracting "40" from both sides, we get

⇒  K_{m}+40-40=50-40

⇒  K_{m}=10 \ \mu M

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3 years ago
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Most likely basalt....

6 0
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Zacharias Janssen

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What is the percent yield if 3.47 g of copper is produced when 1.87 g of aluminium is reacted with excess of copper (II) sulfato
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5 0
2 years ago
Given the following equation: Cu + 2 AgNO3 ---> Cu(NO3)2 + 2
Temka [501]

Given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

<h3>How to calculate mass of substances?</h3>

The mass of a substance can be calculated using the following steps:

Cu + 2AgNO3 = Cu(NO3)2 + 2Ag

1 mole of Cu react with 2 moles of AgNO3

  • Molar mass of AgNO3 = 169.87 g/mol
  • Molar mass of Cu = 63.5g/mol

moles of AgNO3 = 262g/169.87g/mol = 1.54mol

1.54 moles of AgNO3 will react with 0.77 moles of Cu.

mass of Cu = 0.77 × 63.5 = 48.97g

Therefore, given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.

Learn more about mass at: brainly.com/question/6876669

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