<span>The sun is currently a hot ball of glowing gases that is considered as a star. It is the center of our solar system. Its power is responsible for bringing life to this planet and it also affects the orbits of distant planets like Neptune and Pluto. Without it, Earth will not have the capacity to sustain life and maintain its balance.<span>
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Answer:
2023857702.507m
Explanation:
recall from newton's law of gravitation
G=gravitational constant
mshew=50g
melephant=5*10^3kg
rearth=radius of the earth 6400km or 6400000m
mearth= masss of the earth
Gm(shrew)m(earth)/r(earth)^2 = Gm(elephant)m(earth)/r^2
strike out the left hand side and right hand side variables
m(shrew)/r(earth)^2 = m(elephant)/r^2
r^2 = m(elephant).r(earth)^2 / m(shrew) .........make r^2 the subject of the equation
r^2=
r^2=40960000000000
r=2023857702.507m
<h2>
Answer: destroy all information about its speed or momentum</h2>
The Heisenberg uncertainty principle postulates that the fact that <u>each particle has a wave associated with it</u>, imposes restrictions on the ability to determine its <u>position</u> and <u>speed</u> at the same time.
In other words:
<h2>It is impossible to measure <u>simultaneously </u>(according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle. </h2>
So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity.
It should be noted that this uncertainty does not derive from the measurement instruments, but from the measurement itself. Because, even with the most precise devices, the uncertainty in the measurement continues to exist.
Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.
I = pressure amplitude given = 0.2 W/m²
dB = decibel reading
decibel reading from the pressure amplitude is given as
dB = 10 log₁₀ (I/10⁻¹²)
inserting the values in the above equation
dB = 10 log₁₀ (0.2/10⁻¹²)
dB = 10 log₁₀ (2 x 10⁻¹/10⁻¹²)
dB = 10 log₁₀ (2 x 10⁻¹.10¹²)
dB = 10 log₁₀ (2 x 10¹²⁻¹)
dB = 10 log₁₀ (2 x 10¹¹)
dB = 113.01 db
hence the decibel reading comes out to be 113.01 db
Well based on the three I would think it's C
