Answer:
percentage change in volume = 0.00285 %
Explanation:
given data
bulk modulus = 3.5 ×
N/m²
bulk stress =
N/m²
solution
we will apply here bulk modulus formula that is
bulk modulus =
...............1
put here value and we get
3.5 ×
=
solve it we get
bulk strain = 2.8571 ×
and
bulk strain =
so that percentage change in volume is = 2.8571 ×
× 100
percentage change in volume = 0.00285 %
Answer: true
Explanation:
it flows faster over the top of the wing because the top is more curved than the bottom of the wing. However
Answer:
cross-weight is used to tighten it up.
Explanation:
and yes this is important because Cross-weight percentage compares the diagonal weight totals to the car's total weight.
hope this help
(mark this answer as an brainliest answer)
Answer:
17.799°
Explanation:
When the bullet hits the block at that time the momentum is conserved
So, initial momentum = final momentum

So 

Now energy is also conserved
So 

Answer:
The power developed in HP is 2702.7hp
Explanation:
Given details.
P1 = 150 lbf/in^2,
T1 = 1400°R
P2 = 14.8 lbf/in^2,
T2 = 700°R
Mass flow rate m1 = m2 = m = 11 lb/s Q = -65000 Btu/h
Using air table to obtain the values for h1 and h2 at T1 and T2
h1 at T1 = 1400°R = 342.9 Btu/h
h2 at T2 = 700°R = 167.6 Btu/h
Using;
Q - W + m(h1) - m(h2) = 0
W = Q - m (h2 -h1)
W = (-65000 Btu/h ) - 11 lb/s (167.6 - 342.9) Btu/h
W = (-65000 Btu/h ) - (-1928.3) Btu/s
W = (-65000 Btu/h ) * {1hr/(60*60)s} - (-1928.3) Btu/s
W = -18.06Btu/s + 1928.3 Btu/s
W = 1910.24Btu/s
Note; Btu/s = 1.4148532hp
W = 2702.7hp