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3 years ago

Which conditions are low air pressure systems usually associated with?

Physics

2 answers:

-BARSIC- [3]3 years ago

8 0

Answer:

Cloudy And Wet !!!

Explanation:

Inga [223]3 years ago

4 0

cloudy, wet weather

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Sally and Sam are in a spaceship that comes to within 16,000 km of the asteroid Ceres. Determine the force Sally experiences, in

Diano4ka-milaya [45]

Answer:

0.017 N

Explanation:

The relevant relation is ...

F = GMm/r²

where G is the universal gravitational constant, 6.67408 × 10^-11 m^3·kg^-1·s^-2, M and m are the masses of the objects, and r is the distance between them.

Filling in the given numbers, we find the force to be ...

F = (6.67408 × 10^-11 m^3·kg^-1·s^-2)(8.7 × 10^20 kg)(77 kg)/(1.6 × 10^7 m)^2

where m in this expression is the unit "meters".

F = 6.67408 · 8.7 · 77/2.56 × 10^(-11 +20 -2·7) N ≈ 0.017 N

The asteroid exerts a force of about 0.017 N on Sally.

<em>Additional comment</em>

That's about 0.000023 times the force of Earth's gravity.

7 0

3 years ago

4.7 cm. The tube is sealed at one end and loaded with lead shot to give it a total mass of M = 130 g. The tube floats in water (

babunello [35]

Answer:

Depth is 7.49cm

Explanation:

Given that;

The diameter of tube is (D)=4.7cm

Area of the tube is =πD^2/4

Area is 3.142*4.7*4.7/4=17.35cm2

Mass(M)=130g

Density =1g/cm^3

Recall that Density =mass /volume

Hence volume =130/1=130cm^3

Also note

Volume=area*depth

130=17.35*depth

Depth=130/17.35=7.49cm

6 0

3 years ago

A merry-go-round on a playground consists of a horizontal solid disk with a weight of 805 N and a radius of 1.58 m. A child appl

lozanna [386]

Answer:

The value is $KE = 259.6 \ J$

Explanation:

From the question we are told that

The weight of the horizontal solid disk is $W = 805 \ N$

The radius of the horizontal solid disk is $r = 1.58 \ m$

The force applied by the child is $F = 49.5 \ N$

The time considered is $t = 2.95 \ s$

Generally the mass of the horizontal solid disk is mathematically represented as

$m_h = \frac{W}{ g}$

=> $m_h = \frac{805}{ 9.8 }$

=> $m_h = 82.14 \ N$

Generally the moment of inertia of the horizontal solid disk is mathematically represented as

$I = \frac{1}{2} * m * r^ 2$

=> $I = \frac{1}{2} * 82.14 * 1.58^ 2$

=> $I = 102.5 \ kg \cdot m^2$

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

$T = I * \alpha = F * r$

=> $\alpha = \frac{ F * r }{ I }$

=> $\alpha = \frac{ 49.5 * 1.58 }{ 102.53 }$

=> $\alpha = 0.7628$

Gnerally from kinematic equation we have that

$w = w_o + \alpha t$

Here $w_o$ is the initial angular velocity velocity of the horizontal solid disk which is $w_o = 0\ rad/s$

$w = 0 + 0.7628 * 2.95$

=> $w = 2.2503 \ rad/s$

Generally the kinetic energy is mathematically represented as

$KE = \frac{1}{2} * I * w^2$

=> $KE = \frac{1}{2} * 102.53 * 2.2503 ^2$

=> $KE = 259.6 \ J$

8 0

3 years ago

Question 1 of 10

ahrayia [7]

Answer:

its c

Explanation:i am big brain give me brainilest

7 0

3 years ago

Read 2 more answers

May I get some help please?

ziro4ka [17]

Arrows point away from both north and south.

7 0

3 years ago