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Ostrovityanka [42]
3 years ago
5

Caculate the acceleration of an airplane that goes from 0 knots to 400 knots in 8 seconds

Physics
1 answer:
mafiozo [28]3 years ago
3 0
400 divided by 8 is 50, so its acceleration is 50 knots per second, meaning its speed is increasing by 50 every second.
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Will the temperature of a plastic or wooden spoon be more than the temperature of a metal spoon if you put both of these in a cu
Alja [10]

Answer:

no

Explanation:

the metal spoon would be higher temperature

7 0
3 years ago
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A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len
ale4655 [162]

Answer:

(75 x 0.02) = 1.5 N

Explanation:

7 0
3 years ago
Two students stand poised to leap off a high dive structure into the swimming pool below. Student B is twice as massive as stude
iogann1982 [59]

Answer: option (D)

Explanation:

The potential energy of each of the students is given below as

P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.

The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as

P.E ( student B) =2mgh = 2(mgh)

Recall that the relationship between potential energy and work done is that

Work done = - (change in potential)

For student A, work done = - mgh

For student B, work done = - 2mgh

From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.

8 0
3 years ago
A wire with a linear mass density of 1.17 g/cm moves at a constant speed on a horizontal surface and the coefficient of kinetic
stira [4]

Answer:

The value is B  =  0.2312 \  T

The direction is into the surface

Explanation:

From the question we are told that

   The mass density is  \mu =\frac{m}{L}  = 1.17 \ g/cm =0.117 kg/m

   The coefficient of kinetic friction is  \mu_k  =  0.250

   The current the wire carries is  I =  1.24 \  A

Generally the magnetic force acting on the wire is mathematically represented as

         F_F   = F_B

Here   F_F is the frictional  force which is mathematically represented as

      F_F =  \mu_k *  m *  g

While F_B  is the magnetic force which is mathematically represented as

       F_B  = BILsin(\theta )

Here \theta =90^o is the angle between the direction of the force and that of the current

So

      F_B  = BIL

So

      BIL  =  \mu_k * m * g

=>   B  =  \mu_k *  \frac{m}{L} * [\frac{g}{I} ]

=>   B  =  0.25 *  0.117  * [\frac{9.8}{1.24} ]

=>   B  =  0.2312 \  T

Apply the right hand curling rule , the thumb pointing towards that direction of the current we see that the direction of the magnetic field is into the surface as shown on the first uploaded image

8 0
3 years ago
An electric field of 8.20 ✕ 105 V/m is desired between two parallel plates, each of area 25.0 cm2 and separated by 2.45 mm. Ther
astraxan [27]

Answer:

q = 1.815 \times 10^{-8} C

Charge on one plate is positive in nature and on the other plate it is negative in nature.

Explanation:

E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm

According to the Gauss's theorem in electrostatics

The electric field between the two plates

E = \frac{\sigma }{\varepsilon _{0}}

{\sigma }= E \times {\varepsilon _{0}}

{\sigma }= 8.20 \times 10^{5} \times {8.854 \times 10^{-12}

{\sigma }= 7.26 \times 10^{-6} C/m^{2}

Charge, q = surface charge density x area

q = 7.26 \times 10^{-6} \times 25 \times 10^{-4}

q = 1.815 \times 10^{-8} C

5 0
3 years ago
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