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Leni [432]
3 years ago
6

What is the difference between mass density and weight density?

Physics
1 answer:
Brut [27]3 years ago
8 0

Mass= amount of matter

Weight=the amount of gravity exerted

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What is the magnitude of the force a 25 mC charge exerts on a +2.5 mC charge 16 cm away?
kakasveta [241]
Keep up the good work too
5 0
3 years ago
Sobre un barco, que se mueve en forma rectilínea, y con velocidad constante de 30 [km/h], se mueve un perro en el mismo sentido
almond37 [142]

Answer:

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

Explanation:

Para determinar la velocidad del perro con respecto al observador sentado desde la playa a través del concepto de velocidad relativa, descrito en la siguiente fórmula:

v_{P/B} = v_{P} - v_{B} (1)

Donde:

v_{P/B} - Velocidad del perro relativo al barco, en kilómetros por hora.

v_{P} - Velocidad del perro con respecto al observador, en kilómetros por hora.

v_{B} - Velocidad del barco con respecto al observador, en kilómetros por hora.

Si sabemos que v_{B} = 30\,\frac{km}{h} y v_{P/B} = 10\,\frac{km}{h}, entonces la velocidad del perro con respecto al observador es:

v_{P} = v_{B} + v_{P/B}

v_{P} = 30\,\frac{km}{h} + 10\,\frac{km}{h}

v_{P} = 40\,\frac{km}{h}

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

6 0
3 years ago
What can happen to a photon of light at each change of medium?
Kryger [21]
Give me some answer choices and i will be happy to help
5 0
3 years ago
Which planet moves the fastest and which planet moves slowest? a, b, c, d, e, or f. Explain
Alisiya [41]
D is the point where the planet moves the fastest. This is because it is in the perihelion, where the planet is moving at it’s fastest pace
6 0
2 years ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
Stels [109]

Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Given that

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field at point P

E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta

sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}

r^2=d^2+x^2

So

E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}

Now by integrating above equation

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

4 0
3 years ago
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