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4 years ago

How can you use a magnet to induce a current?

Physics

2 answers:

Vikki [24]4 years ago

8 0

A coil of a wire with a current flowing through it becomes a magnet

Furkat [3]4 years ago

3 0

A coil of wire with a current flowing thru it becomes a magnet

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A 90 kg ice hockey goalie, originally at rest, catches a 0.150 kg hockey puck slapped at him at a velocity of 43.1 m/s. Suppose

Novosadov [1.4K]

Answer:

not sure i think its b

Explanation:

4 0

3 years ago

How many neutrons are needed to initiate the fission reaction shown?

nalin [4]

Answer: One neutron

Explanation:

one neutron 1/0n

Sum up the mass numbers on the right 99 + 135 + 2 = 236.

The sum of the mass numbers on the left should equal 236. 235 + 1 = 236

4 0

4 years ago

Question 4 (2 points)

d1i1m1o1n [39]

Answer:

t = 1.15 + .713 = 1.863 [s]

Explanation:

To solve this problem we must use the following kinematic equation, but first we identify the initial data.

vo = 7 [m/s]

yo = 4 [m]

g = 9.81[m/s^2]

$v_{f}=v_{o}-g*t\\0 = 7 - (9.81*t)\\7 = 9.81*t\\t = 0.713[s]$

The final velocity happens at the moment when the maximum height is reached, at this point the final speed is zero.

$y=y_{o}+v_{o}*t-0.5*g*t^{2}\\ y = 0+ (7*0.713)-0.5*9.81*(0.713)^{2}\\ y = 2.5[m]$

The total elevation will be 2.5 + 4 = 6.5 [m]

Now using again the total height we can find the final velocity.

$v_{f}^2=v_{o}^2+2*g*y\\v_{f}=\sqrt{2*g*y}\\ v_{f}=\sqrt{2*9.81*6.5}\\ v_{f}=11.3[m/s]$

With this final velocity we cand find the time.

$v_{f}=v_{i}+g*t\\11.3=0+9.81*t\\11.3=9.81*t\\t=1.15[s]$

Now we have to sum the two times, the time it takes to go up and the time it takes to go down.

t = 1.15 + .713 = 1.863 [s]

7 0

3 years ago

A coiled spring with coils that are closely spaced then widely then closely then widely then closely, ending with a yellow line

liberstina [14]

Answer:

2, sorry I'm late but my answer is right, I just took the quiz

4 0

3 years ago

Read 2 more answers

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t

mel-nik [20]

Answer:

It will take 0.0611 sec for nerve signal to travel 1.1 m

Explanation:

We have given the nerve cell connecting the spinal card to feet is 1.1 m long

So length d = 1.1 m

And speed of the nerve impulse v = 18 m/sec

We have to find the time for nerve signal to travel that distance

Speed of the nerve signal is given by $v=\frac{d}{t}$

So $t=\frac{d}{v}=\frac{1.1}{18}=0.0611sec$

So it will take 0.0611 sec for nerve signal to travel 1.1 m

5 0

3 years ago