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KengaRu [80]
3 years ago
14

Compute 6.28×1013+7.30×1011.

Chemistry
1 answer:
Simora [160]3 years ago
6 0
6.28×1013+7.30×1011 this =13741.94
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Identify this compound: KClO4
lidiya [134]

Answer: Potassium perchlorate

Explanation:

3 0
2 years ago
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Which substance is a binary acid?
Gelneren [198K]
The answer is going to be hydrochloric acid, therefore hydrochloric acid is a binary acid.
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The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water.
avanturin [10]

a. 0.137

b. 0.0274

c. 1.5892 g

d. 0.1781

e. 5.6992 g

<h3>Further explanation</h3>

Given

Reaction

2 C4H10 + 13O2 -------> 8CO2 + 10H2O

2.46 g of water

Required

moles and mass

Solution

a. moles of water :

2.46 g : 18 g/mol = 0.137

b. moles of butane :

= 2/10 x mol water

= 2/10 x 0.137

= 0.0274

c. mass of butane :

= 0.0274 x 58 g/mol

= 1.5892 g

d. moles of oxygen :

= 13/2 x mol butane

= 13/2 x 0.0274

= 0.1781

e. mass of oxygen :

= 0.1781 x 32 g/mol

= 5.6992 g

6 0
3 years ago
There are three subatomic particles. the particle that is charged positively in the nucleus is called the
Sholpan [36]
It is called a proton I hope this helps
5 0
3 years ago
Assuming the same temperature and pressure for each gas, how many milliliters of carbon dioxide are produced from 16.0 mL of CO?
Vlada [557]

Answer:

V_{CO_2}=16.0mL

Explanation:

Hello,

In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:

2CO(g)+O_2(g)\rightarrow 2CO_2(g)

We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:

n_{CO}V_{CO}=n_{CO_2}V_{CO_2}

Thus, solving for the yielded volume of carbon dioxide we obtain:

V_{CO_2}=\frac{n_{CO}V_{CO}}{n_{CO_2}} =\frac{2mol*16.0mL}{2mol}\\ \\V_{CO_2}=16.0mL

Best regards.

4 0
3 years ago
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