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KengaRu [80]
4 years ago
14

Compute 6.28×1013+7.30×1011.

Chemistry
1 answer:
Simora [160]4 years ago
6 0
6.28×1013+7.30×1011 this =13741.94
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Iron and aluminum are examples of _____________.<br><br> <br><br>​
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Answer:

Iron and aluminum are examples of metals, along with copper, iron, (etc.)

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The Earth only has a limited supply of fresh water; eventually, we will have to use ocean water. We will purify ocean water thro
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I believe it is all of the above
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Give an example of a specialized cell.
Gre4nikov [31]

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Muscle cell

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The prefix ‘kilo-‘ means a thousand.
Blababa [14]

Answer:

0.97 kg, 1.0kg

Explanation:

As you have mentioned in the question, to convert kilo-gram to grams, this conversion is used, 1 kilogram = 1,000 grams

Initially, when one has to convert from one unit to another, there is a lot of confusion. To avoid any such, multiply and divide the number with units to which it has to be converted.

Here,

970 g = 970 g \times\frac{1 kg}{1 kg}

This makes no difference to the number.

970 g =  970 g \times\frac{1 kg}{1000 g}

As, 1 kg= 1,000 g

970 g =  \frac{970}{1000} kg

970 g = 0.97 kg

Rounding this off to the nearest tenth of a kilogram.

The tenths place is immediately to the right of the decimal point.

Here, 9 is at the tenth's place. Round the tenth's place up if the digit at hundredth's place is greater than or equal to 5. Since, 7 > 5, up the number at tenth's place.

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8 0
3 years ago
If iodine-131 has a half-life of 8 days, how much of a 64.0 g sample of iodine-131 will remain after 32 day?
Mariulka [41]

Answer:

4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.

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Half life (t1/2) = 8 days

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Elapsed time (t) = 32 days

Mass remaining (Nt) = ?

Using the half life equation we can obtain the mass remaining (Nt)

Nt = No (1/2) ^t/t1/2

Substituting the values, we have;

Nt = 64 * ( 1/2 ) ^32/8

Nt = 64 * (1/2) ^4

Nt = 64 * 0.0625

Nt = 4 g

So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.

8 0
3 years ago
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