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3 years ago

The atomic weight of boron is reported as 10.81, yet no atom of boron has the mass of 10.81 amu. explain

1 answer:

7 0

Boron has a lot of different isotopes, most of which having a very short half life (ranging from 770 milliseconds for Boron-8 down to 150 yoctoseconds for boron-7). But the two isotopes Boron-10 and Boron-11 are stable with about 80.1% of the naturally occurring boron being boron-11 and the remaining 19.9% being boron-10. The weighted average weight of those 2 isotopes has the value of 10.81. The reason they use the average mass of an element for it's atomic weight is because elements in nature are rarely single isotopes. The weighted average allows us to easily compare relative number of atoms of one element against relative numbers of atoms of another element assuming that the experimenters are getting isotope ratios close to their natural ratios.

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2 years ago

WILL GIVE BRAINLIEST Explain why HS2 has a bent geometry, while BeH2 has a linear geometry.

Natali5045456 [20]

Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

Structure of H2S :

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) 3s(2 )3p(4)

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these 6 electrons ,

2 electrons are formed in bonding with Hydrogen

Rest 4 are non- bonding and present as lone - pair

H2S exist - sp3 hybridisation

There are 2-Lone pair on S in H2S (look at the image attached)

Structure of H2S :

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.

Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S shifts way from lone pair

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