Answer:
6.25 g of Carbon is in Excess
Explanation:
The balance chemical equation is as follow:
C + O₂ → CO₂
Step 1: Calculate Moles of O₂ as:
Moles = Mass / M/Mass
Moles = 50 g / 32 g/mol
Moles = 1.562 mol of O₂
Step 2: Calculate Moles of C as;
Moles = 25 g / 12 g/mol
Moles = 2.08 mol
Step 3: Calculate the Limiting reagent:
According to equation,
1 moles of O₂ reacted with = 1 mole of C
So,
1.562 moles of O₂ will react with = X moles of C
Solving for X,
X = 1 mol × 1.562 mol / 1 mol
X = 1.562 mol of C
While we are provided with 2.08 mol of C. Means C is in excess.
Step 4: Calculate amount of Excess C as;
Excess Moles = Given Moles - Used Moles
Excess Moles = 2.08 mol - 1.562 mol
Excess Moles = 0.521 moles
Step 5: Converting Excess moles to Mass as:
Mass = Moles × M.Mass
Mass = 0.521 mol × 12 g/mol
Mass = 6.25 g
