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grigory [225]
3 years ago
9

URGENT Best answer gets Brainliest! Mg+ 2HCI ——> MgCI2+ H2

Chemistry
1 answer:
avanturin [10]3 years ago
6 0

Answer:

Reaction type: Single displacement

Reactant: Magnesium

Product: Dihydrogen - H2

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Which ion in the ground state has the same electron configuration as an atom of neon in the ground state?
Ainat [17]
  • Cl-

Lets see how

  • Z for Cl is 9
  • One electron is added so new Z=10

Electronic configuration

  • 1s²2s²2p⁶

Or

  • [Ne]

option B is correct

6 0
2 years ago
Read 2 more answers
When a radioactive isotope releases an alpha particle, the atomic number of the atom is (2 points)
natali 33 [55]
When alpha decay takes place, two protons and two neutrons are forcefully ejected from the nucleus in a way that looks very similar to a Helium nucleus. This type of decay causes the atomic mass of the parent particle to drop by four (four particles lost), but the atomic number drops by only two (two protons lost). Therefore, your answer is C.
8 0
3 years ago
Read 2 more answers
What are the symbols for the elements with the following valence electron configurations? List all.a. s2d1b. s2p3c. s2p
maria [59]

Answer:

Sc : 4s 2 3d 1

 Y : l 5s 2 4d 1

La : 6s 2 5d 1

Ce : 6s 2 4f 1 5d 1

Gd : 6s 2 4f 7 5d 1

Lu : 6s 2 4f 14 5d 1

Ac : 7s 2 6d 1

Pa : 7s 2 5f 2 6d 1

U : l 7s 2 5f 3 6d 1

Np : 7s 2 5f 4 6d 1

Cm : 7s 2 5f 7 6d 1

b. s2p3

he pnictogens:

N l : 2s 2 2p 3

P l : 3s 2 3p 3

As : 4s 2 3d 10 4p 3

Sb : 5s 2 4d 10 5p 3

Bi : 6s 2 4f 14 5d 10 6p 3

Mc : 7s 2 5f 14 6d 10 7p 3

c.The noble gases:

Ne : 2s 2 2p 6

Ar : 3s 2 3p 6

Kr : 4s 2 3d 10 4p 6

Xe : 5s 2 4d 10 5p 6

Rn : 6s 2 4f 14 5d 10 6p 6

Og : 7s 2 5f 14 6d 10 7p 6

Explanation: From the periodic tables we can drive elements with the electronic configuration

Sc : 4s 2 3d 1

 Y : l 5s 2 4d 1

La : 6s 2 5d 1

Ce : 6s 2 4f 1 5d 1

Gd : 6s 2 4f 7 5d 1

Lu : 6s 2 4f 14 5d 1

Ac : 7s 2 6d 1

Pa : 7s 2 5f 2 6d 1

U : l 7s 2 5f 3 6d 1

Np : 7s 2 5f 4 6d 1

Cm : 7s 2 5f 7 6d 1

b. s2p3

he pnictogens:

N l : 2s 2 2p 3

P l : 3s 2 3p 3

As : 4s 2 3d 10 4p 3

Sb : 5s 2 4d 10 5p 3

Bi : 6s 2 4f 14 5d 10 6p 3

Mc : 7s 2 5f 14 6d 10 7p 3

c.The noble gases:

Ne : 2s 2 2p 6

Ar : 3s 2 3p 6

Kr : 4s 2 3d 10 4p 6

Xe : 5s 2 4d 10 5p 6

Rn : 6s 2 4f 14 5d 10 6p 6

Og : 7s 2 5f 14 6d 10 7p 6

3 0
3 years ago
Consider the following system at equilibrium:D(aq)+E(aq)<=>F(aq)Classify each of the following actions by whether it cause
igomit [66]

Explanation:

D(aq) + E(aq) <=> F(aq)

This question is based on Le Chatelier's principle.

Le Chatelier's principle is an observation about chemical equilibria of reactions. It states that changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system in order to achieve a new equilibrium state.

Increase D

D is a reactant. if we add reactants to the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Increase E

E is a reactant. if we add reactants to the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Increase F

F is a product.  If we add additional product to a system, the equilibrium will shift to the left, in order to produce more reactants. The reaction would shift to the left.

Decrease D

if we remove reactants from the system, equilibrium will  be shifted to the left.

Decrease E

if we remove reactants from the system, equilibrium will  be shifted to the left.

Decrease F

if we remove products from the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Triple D and reduce E to one third

no shift in the direction of the net reaction, Both changes cancels each other.

Triple both E and F

no shift in the direction of the net reaction, Both changes cancels each other.

4 0
3 years ago
___CH4 + ___O2 → ___CO2 + ___H2O When you burn natural gas in the laboratory, methane burns. What numbers fill in the blanks to
Hitman42 [59]

Answer:

The coefficient are 1,2,1,2 ( option B is correct)

Explanation:

Step 1: Data given

Methane = CH4

Burning methane = CH4 + O2

Step 2: The unbalanced equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

Step 3: Balancing the equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

On the left side we have 4x H (in CH4), on the right side we have 2x H (in H2O). To balance the amount of H, on both sides, we have to multiply H2O (on the right side by 2).

CH4(g) + O2(g) → CO2(g) + 2H2O(g)

On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in 2H2O). To balance the amount of O on both sides, we have to multiply O2 (on the left side by 2).

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

The coefficient are 1,2,1,2 ( option B is correct)

3 0
3 years ago
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