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Margaret [11]
2 years ago
14

A building is 6m high, and it is 80m from a converging camera lens. If the camera forms an image which is 6 mm high, (a) What is

the magnification? (b) How far must the camera film be behind the lens for the image to be formed?
Physics
1 answer:
Lostsunrise [7]2 years ago
5 0

Answer:

Explanation:

Two aircrft pand qare flyingatthe same speed 300m the diraction along tothe diraction of the veloctiy

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Acetone is a flammable solvent used in the making of plastics. The density is 790kg/m3. to convert 790kg/m3 to g/cm3​
Artist 52 [7]

Answer: 0.790 g/cm3

Explanation:

The density of acetone is 790 Kg/m3.

To convert from Kg to g we multiply by 1000 (1 Kg = 1000 g)

To convert from m3 to cm3 we multiply by 10∧6

So, The density of acetone in (g/cm3) = (790 x 1000) / (10∧6) = 0.79 g/cm3

4 0
3 years ago
a wire carries 15 A. You form it into a singleturn circular loop with magnetic field 80 µT at the loop center. What is the loop
solong [7]
Use the formula B(at the center)= (4 pi * 10^(-7) ) * I (current)   / ( 2 radius)
and you will get the answer that will be 6.

3 0
3 years ago
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In an arcade game a 0.099 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releas
Sonja [21]

Answer:

The speed of disk is 1.98 \frac{m}{s}

Explanation:

Given:

Mass of m = 0.099 kg

Spring constant k = 244 \frac{N}{m}

Compression of spring x = 4 \times 10^{-2} m

From energy conservation theorem,

Spring potential energy converted into kinetic energy,

   \frac{1}{2} m v^{2} = \frac{1}{2} k x^{2}

  v = \sqrt{\frac{k x^{2} }{m} }

  v = \sqrt{\frac{244 \times 16 \times 10^{-4} }{0.099} }

  v = 1.98 \frac{m}{s}

Therefore, the speed of disk is 1.98 \frac{m}{s}

8 0
3 years ago
Two objects (38.0 and 17.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
fgiga [73]

Answer:

a) 3.7 m/s^2

b) 231.8 N

Explanation:

Let m1 be mass of the first object (m1 = 38.0 kg) and let m2 be the mass of the second object (m2 = 17.0 kg ). Let a be the acceleration of the two objects. Let F1 be the force of gravity exerted on m1 and F2 be the force of gravity exerted on m2. Let M = m1 +m2

a)

F1 = m1g and F2 = m2g

So Fnet = F1 + F2

Since the pulleys will move in different directions when accelerating...

Fnet = F1 - F2

M×a = m1g - mg2

M×a = g×(m1 -m2)

a = g×(m1 - m2)/M

a = 9.8×(38 - 17)/(38 + 17)

a = 3.7 m/s^2

b)

Looking at the part for m2

Fnet  = T - m2g

-m2×a = T - m2g

T = m2(g - a)

T = 231.8 N

7 0
3 years ago
An arctic fox has thick, dense fur in the winter and much shorter fur in the summer. How does this help the fox maintain homeost
Sonja [21]
The increased thickness of the fox's fur allows the fox to warmer in cold temperatures, while the shorter fur does the opposite.
4 0
4 years ago
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