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3 years ago

15

List two ways in which heterogeneous mixtures differ from elements.

1 answer:

Georgia [21]3 years ago

3 0

Heterogeneous mixtures differ from elements in two ways. First, elements are not a mixture at all; they are pure substances. Heterogeneous mixtures are not pure. The other way is that a heterogeneous mixture can be separated by physical means; elements can't be separated at all; if the elements are separated, it will change their composition. Hope this helps

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n-Butane fuel (C4H10) is burned with the stoichiometric amount of air. Determine the mass fraction of each product. Also, calcul

tia_tia [17]

Answer:

0.1852
0.0947
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3.0345 kg CO $_{2}$ / Kg C $_{4}$ H $_{10}$
15.3848 Kg air / kg C $_{4}$ H $_{10}$

Explanation:

Molar masses of each product are :

Butane = 58 kg /kmol

Oxygen = 32 kg/kmol

Nitrogen = 28 kg/kmol

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<u><em>1) Calculate the mass fraction of carbon dioxide </em></u>

= ( 4 * 44 ) / ( (5 * 18) + (4 *44 )+ (24.44 * 28) )

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<em><u>2) Calculate the mass fraction of water </u></em>

= ( 5 * 18 ) / (( 5* 18 ) + ( 4*44) + ( 24.44 * 28 ))

= 90 / 950.32

= 0.0947

<em><u>3) Calculate the mass fraction of Nitrogen </u></em>

= (24.44 * 28 ) / ((4 * 44 ) + ( 24.44 * 28 ) + ( 5 * 18 ))

= 684.32 / 950.32

= 0.7201

<em><u>4) Calculate the mass of Carbon dioxide in the products</u></em>

Mco2 = ( 4 * 44 ) / 58 = 3.0345 kg CO $_{2}$ / Kg C $_{4}$ H $_{10}$

<u>5) Mass of Air required per unit of fuel mass burned </u>

Mair = ( 6.5 * 32 + 24.44 *28 ) / 58 = 15.3848 Kg air / kg C $_{4}$ H $_{10}$

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Leokris [45]

0.06105 moles is the number of moles of water lost.

<h3>What is molar mass?</h3>

Molar mass is defined as the mass in grams of one mole of a substance.

Given data:

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These quantities are related by the following equation;

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Moles = $\frac{1.1 }{18.016}$ = 0.06105 moles.

Hence, the 0.06105 moles is the number of moles of water lost.

Learn more about molar mass here:

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