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MAXImum [283]
3 years ago
5

Research benzene and list two modern-day commercial uses for his chemical​

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Benzene is used for pesticides and detergents. It is also used for other things besides these.

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What will be the n-factor for Ba (MnO4)2 in acidic medium?(where it behaves as an oxidant)
Art [367]
Ba(MnO₄)₂ → Ba²⁺ + 2MnO₄⁻

MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O   n=5
3 0
3 years ago
An electrically neutral atom consists of 15 neutrons, 13 electrons, and a
nikitadnepr [17]

Answer:

Answer:

28

Explanation:

it states that the atom is neutral, meaning the number of electrons and protons are the same. so if there are 13 electrons, there are 13 protons. And the mass number is neutrons plus protons. So 13+15 is 28

3 0
3 years ago
Uhu khanay sai kia hota hai
trapecia [35]
Pardon me uh hmm interesting
3 0
3 years ago
The amount of water vapor in a given volume of air is ______________ .The amount of water vapor in the air at any one time depen
Eduardwww [97]

Answer:

The amount of water vapor in a given volume of air is humidity.The amount of water vapor in the air at any one time depends on temperature . Warmer air holds more water than cooler air. Clouds form when humidity is low and thetemperature is high . Relative humidity is defined as the amount of water vapor in the air divided by the amount that would have to be present in the same air to form a cloud or condense on a surface. Dew is related to the humidity of the previous day. The air temperature at which water vapor in the air condenses onto cool surfaces is the dew point.

Explanation:

8 0
2 years ago
A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing point depression of
sergij07 [2.7K]
From the equation; ΔTf = Kf × m
Where, Kf for water = 1.853 K kg/mole; m is the molarity = number of solute/amount of solvent in kg.
Glucose is the solute whose molecular mass is 180 g/mole and water is the solvent. 
Moles of solute = 15.5/180 = 0.0861 moles
Amount of solvent in kg = 245/1000 = 0.245 Kg
Therefore; molarity = 0.0861/0.245 = 0.3515 moles/Kg
Therefore; ΔTf = 1.853 × 0.3515 = 0.6513 K
Hence; the depression in freezing point is 0.6513 
The freezing point of solution will therefore be;
= 273 - 0.6513 = 272.3487 K

7 0
3 years ago
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