Answer:
The amplitude of the wave is 0.02 m.
Explanation:
Given that,
Maximum speed = 2.0 m/s
Maximum acceleration = 200 m/s²
We need to calculate the angular frequency
Using formula of angular frequency
Put the value into the formula
We need to calculate the amplitude of the wave
Using formula of velocity
Put the value into the formula
Hence, The amplitude of the wave is 0.02 m.
Answer:
a. the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon; the force is 1.38 × 10⁸ greater than muon
Explanation:
F= ma
v²=u² -2aS
(1.56 ✕ 10⁶)²=(2.40 ✕ 10⁶)²-2a(1220)
a=1.36×10⁹m/s²
recall
F=ma
F = 1.88 ✕ 10⁻²⁸ kg × 1.36×10⁹m/s²
F= 2.55 × 10⁻¹⁹N
the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon
F/mg= 2.55 × 10⁻¹⁹/ (1.88 ✕ 10⁻²⁸ × 9.8)
= 1.38 × 10⁸
Period of a simple pendulum = 2π √(L/G)
(360s/100) = 2π √(1.2m/G)
1.8s / π = √1.2m / √G
√G · (1.8s/π) = √1.2m
√G = (π · √1.2m) / 1.8s
Square each side:
G = π² · 1.2m / 3.24 s²
G = (1.2 · π² / 3.24) m/s²
G = 3.66 m/s²
So I just went and looked up Mars gravity. Floogle says it's 3.711 m/s² there.
That seems awfully close ... only 1.4% greater than our astronauts measured.
You don't suppose . . . . .
C. meter per second
Velocity and speed share the same SI unit.