Answer:
1.37 rad/s
Explanation:
Given:
Total length of the tape is, 
m
Total time of run is, 
hours
We know, 1 hour = 3600 s
So, 2.1 hours = 2.1 × 3600 = 7560 s
So, total time of run is, 
s
Inner radius is, 
Outer radius is, 
Now, linear speed of the tape is, 
Let the same angular speed be 
.
Now, average radius of the reel is given as the sum of the two radii divided by 2.
So, average radius is, 
Now, common angular speed is given as the ratio of linear speed and average radius of the tape. So,
Therefore, the common angular speed of the reels is 1.37 rad/s.
Answer:
The average angular acceleration is 
Explanation:
From the question we are told that
From the question we are told that
The length of the bat is 
\
The initial linear velocity is 
The time is 
The velocity at t is 
Generally average angular acceleration is mathematically represented as
Where 
is the finial angular velocity which is mathematically evaluated as
and 
is the initial angular velocity which is zero since initial linear velocity is zero
So
The given question is incomplete. The complete question is as follows.
An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on 1 of 36 possible sites for adsorption. Calculate the entropy of this system.
Explanation:
It is known that Boltzmann formula of entropy is as follows.
s = k ln W
where, k = Boltzmann constant
W = number of energetically equivalent possible microstates or configuration of the system
In the given case, W = 36. Now, we will put the given values into the above formula as follows.
s = k ln W
= 
= 
Thus, we can conclude that the entropy of this system is .
