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elena-s [515]
3 years ago
5

his chemical equation represents the burning of methane, but the equation is incomplete. What is the missing coefficient in both

the reactants and the products? CH4 + ____O2 → CO2 + ____H2O
Chemistry
1 answer:
Aleksandr [31]3 years ago
7 0
It’s Supposed to be CH4 + 2O2 > CO2 + 2H2O
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Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight
Salsk061 [2.6K]

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒  Mass \ of \ Butane = Density\times Volume

On putting the estimated values, we get

⇒                              =0.579\times 7.96

⇒                              =4.60 \ g

6 0
3 years ago
5. For the following equation:
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the correct answer is option A copper and silver

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Read 2 more answers
CH3OH can be synthesized by the following reaction.
puteri [66]

Answer:

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

Explanation:

Step 1: Data given

CO(g)+2H2(g)?CH3OH(g)

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.04 g/mol

Step 2: What volume of H2 gas (in L), measured at 754mmHg and 90?C, is required to synthesize 23.0g CH3OH?

Pressure = 754 mmHg = 0.992 atm

Temperature = 90°C = 363 Kelvin

mass of CH3OH produced = 23.0 grams

Step 3: Calculate moles of CH3OH

Moles CH3OH = mass CH3OH / Molar mass CH3OH

Moles CH3OH = 23.0 grams / 32.04 g/mol

Moles CH3OH = 0.718 moles

Step 4: Calculate moles of H2

For 1 mol of CO consumed, we need 2 moles of H2 to produce 1 mol of CH3OH

For 0.718 moles CH3OH produced, we have 2*0.718 moles =1.436 moles of H2 and 0.718 moles of CO

Step 5: Calculate volume of H2

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 1.436 moles H2

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (1.436*0.08206*363)/0.992

V = 43.12 L

Step 6: Calculate volume of CO

p*V = n*R*T

with p = the pressure = 0.992 atm

with V the volume = TO BE DETERMINED

with n = the number of moles = 0.718  moles CO

with R = the gasconstant = 0.08206 L*atm/ K*mol

with T = the temperature = 363 Kelvin

V = (n*R*T)/p

V = (0.718*0.08206*363)/0.992

V = 21.56 L

A: There is 43.12 Liter of H2 needed

B: There is 21.56 liter of CO needed

3 0
3 years ago
What are the names of the compound (with roman numeral)? Na2SO4
sergiy2304 [10]

Answer:

Sodium sulphate

Or sodium (I) sulphate

Explanation:

7 0
3 years ago
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