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asambeis [7]
2 years ago
8

A loaded garbage truck has low acceleration. It takes pm 10 seconds to go from 0 to 100 What is the acceleration of the garbage

truck How much slower is the acceleration of the garbage truck compared to the acceleration of the sports car in Figure Garbage truck I Speed goes from 010100 in 10 seconds

Physics
1 answer:
Alexus [3.1K]2 years ago
3 0

You didn't give us a photo of Figure 4-18, so we don't know anything about
the sports car.  But here's how to answer the question on your own:

       Acceleration = (change in speed) divided by (time for the change)
and
       Change in speed  =  (end speed) minus (start speed)

So, the garbage truck's acceleration is ...

                                
  (100 km/hr - 0)  /  (10 sec)

                               =      10 km/hr  per second .

Calculate the acceleration of the sports car the same way,
and then you can compare them.
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trasher [3.6K]

Answer

The answer for the first one I think is false.

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8 0
2 years ago
Read 2 more answers
How do you calculate the power in a circuit or device if given the current and the resistance?
Drupady [299]

Answer:

you use the Ohms law so to find the voltage you would need to multiply the current by the resistance which gives you the power.

V- voltage

I- current

R- resistance

V= I×R

5 0
2 years ago
Which goes into which category?
Pavel [41]

Evidence of Chemical Change:

A car rusting

Leaves changing in October

The glow of a light bulb

A white cloudy substance occurs after mixing two substances

Burning toasts

A candle being lit

Evidence of Physical Change:

Water boiling

Yellow and blue paints mixed together

Wax melting

Crushing a rock with a hammer

Hope this helps!

Have a great day!

6 0
3 years ago
A 15.0-μF capacitor is charged by a 130.0-V power supply, then disconnected from the power and connected in series with a 0.280-
SVETLANKA909090 [29]

The resonant frequency of a circuit is the frequency \omega_0 at which the equivalent impedance of a circuit is purely real (the imaginary part is null).

Mathematically this frequency is described as

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

Where

L = Inductance

C = Capacitance

Our values are given as

C = 15*10^{-6}\mu F

L = 0.280*10^{-3}mH

Replacing we have,

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

f = \frac{1}{2\pi}(\sqrt{\frac{1}{(15*10^{-6})(0.280*10^{-3})}})

f= 2455.81Hz

From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.

For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.

7 0
3 years ago
Two sealed 1 l containers full of gas are at room temperature. Container a has a pressure of 4 atm and container b has a pressur
loris [4]

Answer:

The number density of the gas in container A is twice the number density of the gas in container B.

Explanation:

Here we have

P·V =n·R·T

n = P·V/(RT)

Therefore since V₁ = V₂ and T₁ = T₂

n₁ = P₁V₁/(RT₁)

n₂ = P₂V₂/(RT₂)

P₁ = 4 atm

P₂ = 2 atm

n₁ = 4V₁/(RT₁)

n₂ =2·V₁/(RT₁)

∴ n₁ = 2 × n₂

Therefore, the number of moles in container A is two times that in container B and the number density of the gas in container A is two times the number density in container B.

This can be shown based on the fact that the pressure  of the container is due to the collision of the gas molecules on the walls of the container, with a kinetic energy that is dependent on temperature and mass, and since the temperature is constant, then the mass of container B is twice that of A and therefore, the number density of container A is twice that of B.

5 0
3 years ago
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