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bagirrra123 [75]
4 years ago
12

I NEED ANSWERS QUICK

Physics
1 answer:
Dmitry [639]4 years ago
3 0
B. Is the answer but tell me if that is wrong
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A sample of gas is enclosed in a container of fixed volume. Identify which of the following statements are true. Check all that
motikmotik

Answer:

B. If the container is cooled, the gas particles will lose kinetic energy and temperature will decrease.

C. If the gas particles move more quickly, they will collide more frequently with the walls of the container and pressure will increase.

E. If the gas particles move more quickly, they will collide with the walls of the container more often and with more force, and pressure will increase.

#FreeMelvin

7 0
4 years ago
A recent home energy bill indicates that a household used 475475 kWh (kilowatt‑hour) of electrical energy and 135135 therms for
faltersainse [42]

Answer:

Explanation:

Given that,.

A house hold power consumption is

475 KWh

Gas used is

135 thermal gas for month

Given that, 1 thermal = 29.3 KWh

Then,

135 thermal = 135 × 29.3 = 3955.5 KWh

So, total power used is

P = 475 + 3955.5

P =4430.5 KWh

Since 1 hr = 3600 seconds

So, the energy consumed for 1hr is

1KW = 1000W

P = energy / time

Energy = Power × time

E = 4430.5 KWhr × 1000W / KW × 3600s / hr

E = 1.595 × 10^10 J

So, using Albert Einstein relativity equation

E = mc²

m = E / c²

c is speed of light = 3 × 10^8 m/s

m = 1.595 × 10^10 / (3 × 10^8)²

m = 1.77 × 10^-7 kg

Then,

1 kg = 10^6 mg

m = 1.77 × 10^-7 kg × 10^6 mg / kg

m = 0.177mg

m ≈ 0.18 mg

5 0
3 years ago
A sample of polonium-210 was left for 414 days.
jenyasd209 [6]

Answer:

PO(1) = PO(0) / 2       1 refers to 1 half life of PO(0)

PO(2) = PO(1) / 2 = P(0) / 4        amount of PO left after 2 half-lives

PO(3) = PO(2) / 2 = PO(0) / 8     amount of PO left after 3 half-lives

414 da / 138 da = 3       3 half-lives pass in 414 da

PO(0) = 8 PO(3) = 8 * 1.45E-4 g = 1.16E-3 g = .00116 g  after 414 days        

6 0
3 years ago
An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Maksim231197 [3]

Answer:

88.3ms {}^{ - 2}

or 88.3m/s^2

Explanation:

Using suvat where we list everything that we are given

s=49m

u=0m/s

v=93m/s

a=?

t=we are not given this value, so we don't use

using a formula that doesn't involve time:

v {}^{2}  = u {}^{2}  + 2as

rearranging to find acceleration by subtracting u^2 on both sides

v {}^{2}  - u {}^{2}  = 2as

then dividing 2s on both sides

\frac{v {}^{2} - u {}^{2}  }{2s}  = a

\frac{(93) {}^{2}  - (0) {}^{2} }{2 \times(49) }  = 88.3ms {}^{ - 2}

so the acceleration is 88.3ms^-2 (1dp)

3 0
3 years ago
The earth's magnetic field extends from the center of the earth to outer space.
GaryK [48]
Okay...

what was this for...?
4 0
4 years ago
Read 2 more answers
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