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Elden [556K]
3 years ago
15

You exert a force of 75 newtons on a rock. You push and you push, but you can’t budge it. You are exhausted! How much work did y

ou perform?
Physics
1 answer:
dalvyx [7]3 years ago
4 0

Answer:   Work W = 0

Explanation: Work W = F·s. Because rock does not move, s = 0 and

work done is zero.

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A sound wave is an example of an electromagnetic wave in nature. true or false?
Natasha2012 [34]
False. A sound wave is an example of a mechanical wave, not an EM wave.

Hope this helps! :)
5 0
4 years ago
Read 2 more answers
I need the definition or I won't graduate help and thank you
Goryan [66]

Answer:

1. a 2.c 3 b

Explanation:

7 0
3 years ago
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Why do the layers of sedimentary rocks parallel to earth's surface?​
Vedmedyk [2.9K]

Answer:

why do the layers of sedimentary rocks parallel to earth's surface?

Why are sedimentary rocks found on or close to Earth's surface?

Explanation: Erosion breaks existing rocks and turns them into sediments. ... When subjected to heat and pressure deeper in the earth sedimentary rocks are changed into igneous and metamorphic rocks. Because erosion only happens on the earth's surface sedimentary rocks are only formed on the earth's surface.

Explanation:

Why do sedimentary rocks have layers and how these layers are formed?

The different groups of sediments could have been deposited through wind, water, ice, and/or gravity at different intervals of time and compacted on top of each other, until they create a sedimentary rock that has several different types of sediments (possibly from different rock types) in the form of layers.

6 0
2 years ago
Interactive LearningWare 22.2 reviews the fundamental approach in problems such as this. A constant magnetic field passes throug
inessss [21]

Explanation:

The dimension of a single rectangular loop is 0.46 m x 0.68 m.

Magnetic field, B = 3 T

The loop is inclined at an angle of 67 degrees with respect to the normal to the plane of the loop.

It is required to find the magnitude of the average emf induced in the loop if the magnetic field decreases to zero in a time of 0.49 s.

Te induced emf in the loop is given by :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=A\dfrac{dB}{dt}\cos\theta\\\\\epsilon=0.46\times 0.68\times \dfrac{3}{0.49}\times \cos(67)\\\\\epsilon=0.74\ V

So, the magnitude of the average emf induced in the loop is 0.74 V.

7 0
3 years ago
Find the current flowing out of the battery in the circuit. I = [?] A 9.0 V 30 ww 40 Ω www 50 Ω 20Ω 10Ω​
frozen [14]

We need Net resistance

solve from right words

\\ \rm\Rrightarrow R_1=20+10=30\Omega

\\ \rm\Rrightarrow \dfrac{1}{R_2}=\dfrac{1}{30}+\dfrac{1}{50}=\dfrac{5+3}{150}

\\ \rm\Rrightarrow R_2=\dfrac{150}{8}=18.75\Omega

\\ \rm\Rrightarrow \dfrac{1}{R_3}=\dfrac{1}{30}+\dfrac{1}{40}=\dfrac{4+3}{120}

\\ \rm\Rrightarrow R_3=\dfrac{120}{7}=17.14\Omega

\\ \rm\Rrightarrow R_{net}=17.14+18.75=35.89\Omega

Use ohm's law

\\ \rm\Rrightarrow I=\dfrac{V}{R}

\\ \rm\Rrightarrow I=\dfrac{9}{35.89}

\\ \rm\Rrightarrow I\approx 0.25A

7 0
2 years ago
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