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AnnyKZ [126]
3 years ago
9

A 8390 g/hr stream of liquid methyl alcohol, also called methanol, (CH_3OH) at 6.20 atm and 24.0 degree C was held at constant p

ressure, vaporized and brought to 337.0 degree C. At what rate must heat be supplied to this system? Assume that methyl alcohol vapor behaves ideally for the temperature range and pressure given.
Chemistry
1 answer:
deff fn [24]3 years ago
7 0

Answer:

heat must be supplied to the system at a rate of 6670.22 KJ/h

Explanation:

m = 8390 g/h * ( Kg / 1000g )

⇒ m = 8.39 Kg/h

P1 = P2 = 6,20 atm.......... constant pressure

T1 = 24°C = 297 K

T2 = 337.0°C = 610 K

⇒ ΔT = 610 - 297 = 313 K

Q = ?

starting from first law at constant pressure:

  • Qp = ΔH = mCpΔT

∴ Cp (24°C) = 2,54 KJ / Kg°K.......engineering toolbox CH3OH

⇒ Q = ( 8.39 Kg/h ) * ( 2.54 KJ / Kg K ) * ( 313 K )

⇒ Q = 6670.22 KJ/h

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An element that has 2 core electrons and 3 valence electrons
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Answer:

Boron

Explanation:

You can find this by looking at the number of protons in Boron, 5.

Then calculate how many electrons you are given, in this case the 2 core plus the 3 valence equal 5 total electrons

Neutral elements have the same number of protons and electrons, so your answer would be the element with 5 electrons, Boron.

You can also know this by using electron configuration. Since you kow there are 5 electrons then you can use EC to find out where your element is. In this case it is: 1s2 2s2 2p1

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2 years ago
Heat the oxygen to about 150 K. What state of matter is this?
adelina 88 [10]

Answer:

  • <u>Gas</u>

Explanation:

It is easier if you convert the kelvin temperature into Celsius degrees:

  • ºC = T - 273.15 = 150 - 273.15 = -123.15ºC

Now, you know that that is a very cold temperature. Thus, may be the oxygen is not gas any more but it changed to liquid . . . or solid?

You must search for the boiling point and melting (freezing) point of oxygen in tables or the internet. At standard pressure (about 1 atm) they are:

  • Melting point: −218.79 °C,
  • Boiling point: −182.962 °C

That means that:

  • below -218.79ºC oxygen is solid (not our case).
  • between -218.79ºC and -182.962ºC oxygen is liquid (not our case)
  • over -182.962ºC oxygen is a gas. This is our case, because -123.15ºC is a higher temperature than -182.962ºC.

Hence, <em>the state of matter of oxygen at 150K</em>, and standard pressure, is gas.

3 0
3 years ago
Calculate to three significant digits the density of chlorine pentafluoride gas at exactly and exactly . You can assume chlorine
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Answer:

Density is 6.16g/L

Explanation:

<em>... at exactly -15°C and exactly 1atm...</em>

<em />

Using general gas law:

PV = nRT

We can find density (Ratio of mass and volume) in an ideal gas as follows:

P/RT = n/V

<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>

n*MW = m

n = m/MW

P/RT = m/V*MW

P*MW/RT = m/V

<em>Where P is pressure: 1atm;</em>

<em>MW of chlorine pentafluoride: 130.445g/mol</em>

<em>R is gas constant: 0.082atmL/molK</em>

<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>

<em />

Replacing:

P*MW/RT = m/V

1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V

6.16g/L = m/V

<h3>Density of the gas is 6.16g/L</h3>

<em> </em>

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How many bonding electrons are shown below?<br> H-C=C-H
padilas [110]

Answer:

There are total 8 bonding electrons 6 frm the both Carbons and 2 from both hydrogens.

Explanation:

7 0
3 years ago
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