Answer: A volume of 600 mL of 3.0 M solution can be prepared by using 100.0 mL OF 18 M
.
Explanation:
Given: = ?,
,
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 600 mL of 3.0 M solution can be prepared by using 100.0 mL OF 18 M
.
Answer:
82.28g
Explanation:
Given parameters:
Number of moles of hydrogen gas = 7.26 moles
Unknown:
Amount of ammonia produced = ?
Solution:
We have to write the balanced equation first.
N₂ + 3H₂ → 2NH₃
Now, we work from the known to the unknown;
3 moles of H₂ will produce 2 moles of NH₃
7.26 mole of H₂ will produce = 4.84 moles of NH₃
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Mass of NH₃ = number of moles x molar mass = 4.84 x 17 = 82.28g
Answer :
Dipole moments occur when there is a separation of charge. Dipole moments occur due to atoms electronegativity, where one atom has the ability to attract electrons towards it giving it a negative charge and the one deficient in electrons acquire a positive charge called as the bond moment.
But if the bond moments are equal and opposite in direction , they cancel each other and thus there is no net dipole moment in the molecule.
For example: In carbon dioxide , both the -C=O bonds are polar but as the molecule is linear and the the magnetic moments are equal and oppposite, they cancel each other and the molecule is non polar.
