Question

How much iron can be recovered from 25 grams of Fe2O3

Answer 1

25.0g of Fe2O3. 2(55.8)g+3(16.0)g=159.9g. 2(55.8)g/159.6g•100%= 69.9%. 69.9%/100%•25.0g=17.5g of iron recovered

Answer 2

Answer: The mass of iron recovered is 17.5 grams

Explanation:

We are given a chemical compound having chemical formula of $Fe_2O_3$

We know that:

Molar mass of iron (III) oxide = 159.7 g/mol

Mass of iron = 55.8 g/mol

We are given:

Mass of iron (III) oxide = 25 g

To calculate the mass of iron recovered in given amount of iron (III) oxide, we use unitary method:

From 159.7 grams of iron (III) oxide, mass of iron recovered is $(2\times 55.8)g$

So, from 25 grams of iron (III) oxide, mass of iron recovered will be $\frac{(2\times 55.8)}{159.7}\times 25=17.5g$

Hence, the mass of iron recovered is 17.5 grams