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Vlada [557]
3 years ago
14

How much iron can be recovered from 25 grams of Fe2O3

Chemistry
2 answers:
Scilla [17]3 years ago
3 0

25.0g of Fe2O3. 2(55.8)g+3(16.0)g=159.9g. 2(55.8)g/159.6g•100%= 69.9%. 69.9%/100%•25.0g=17.5g of iron recovered

Radda [10]3 years ago
3 0

<u>Answer:</u> The mass of iron recovered is 17.5 grams

<u>Explanation:</u>

We are given a chemical compound having chemical formula of Fe_2O_3

We know that:

Molar mass of iron (III) oxide = 159.7 g/mol

Mass of iron = 55.8 g/mol

We are given:

Mass of iron (III) oxide = 25 g

To calculate the mass of iron recovered in given amount of iron (III) oxide, we use unitary method:

From 159.7 grams of iron (III) oxide, mass of iron recovered is (2\times 55.8)g

So, from 25 grams of iron (III) oxide, mass of iron recovered will be \frac{(2\times 55.8)}{159.7}\times 25=17.5g

Hence, the mass of iron recovered is 17.5 grams

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In the laboratory you dissolve 19.4 g of potassium acetate in a volumetric flask and add water to a total volume of 125 mL. What
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The molarity of the potassium acetate solution given the data is 1.584 M

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of CH₃COOK</h3>
  • Mass of CH₃COOK = 19.4 g
  • Molar mass of CH₃COOK = 98 g/mol
  • Mole of CH₃COOK =?

Mole = mass / molar mass

Mole of CH₃COOK = 19.4 / 98

Mole of CH₃COOK = 0.198 mole

<h3>How to determine the molarity of CH₃COOK</h3>
  • Mole of CH₃COOK = 0.198 mole
  • Volume = 125 mL = 125 / 1000 = 0.125 L
  • Molarity of CH₃COOK = ?

Molarity = mole / Volume

Molarity of CH₃COOK = 0.198 / 0.125

Molarity of CH₃COOK = 1.584 M

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5 0
2 years ago
As an ice cube melts on a table top it transforms from a solid bank with a defined shape to a puddle with a much greater ability
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In a solid state, the molecules have the least amount of energy. They just stick close together and vibrate in place. As the molecules gain more energy, they are able to move around more freely. In the liquid state, the molecules have enough energy to sort of tumble over each other.
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3 years ago
When a highly reactive metal, such as lithium (Li), is mixed with a highly reactive nonmetal, such as chlorine (Cl), they will m
Usimov [2.4K]

Answer:

True

Explanation:

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Based on the balanced equation 2C2H2 + 5O2 → 4CO2 + 2H2O calculate the number of excess reagent units remaining when 52 C2H2 mol
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Answer:

20 molecules of oxygen gas remains after the reaction.

Explanation:

2C_2H_2 + 5O_2\rightarrow 4CO_2 + 2H_2O

Molecules of ethyne = 52

Molecules of oxygen gas = 150

According to reaction, 2 molecules of ethyne reacts with 5 molecules of oxygen gas.

Then 52 molecules of ethyne will react with:

\frac{5}{2}\times 52=130 molecules of oxygen gas.

As we can see that we have 150 molecules of oxygen gas, but 52 molecules of ethyne will react with 130 molecules of oxygen gas. So, this means that ethyne is a limiting reagent and oxygen gas is an excessive reagent.

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20 molecules of oxygen gas remains after the reaction.

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