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2 years ago

A=1/2(a+b)h SOLVE FOR "h"

1 answer:

5 0

Solving equations is a basic skill that you must master to deal with a lot of problems in mathematics, physics, chemistry, administration, economy, and almost every activity where you need to use a formula or a model. to solve for h, you follow these steps: 1) multiply both sides by 2 => 2A = (a+b)h; 2) divide both sides by (b+a) => 2A/ (a+b) = h. So the answer is: h = 2A / (a+b).
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Divide 125 by 1/4 and add 13 to the quotient.<br><br> Plz help

Karo-lina-s [1.5K]

I think the answer is 513

5 0

2 years ago

A certain circle can be represented by the following equation. x^2+y^2+6y-72=0 What is the center of this circle ?

jek_recluse [69]

Answer:

(0, -3)

Step-by-step explanation:

Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."

Rearranging x^2+y^2+6y-72=0, we get x^2 + y^2 + 6y = 72.

x^2 is already a perfect square. Focus on rewriting y^2 + 6y as the square of a binomial: y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:

x^2 + y^2 + 6y + 9 - 9 = 72:

x^2 + (y + 3)^2 = 81

Comparing this to the standard equation of a circle with center at (h, k) and radius r,

(x - h)^2 + (y - k)^2 = r^2. Then h = 0, k = -3 and r = 9.

The center of the circle is (h, k), or (0, -3).

8 0

3 years ago

Find all the missing elements. A=109 C=13 b=6 B=? a=? c=?

sasho [114]

Answer:

B = 58°
a = 6.6896
c = 1.5915

Step-by-step explanation:

Given two angles and the side between them, the first step must be to find the value of the third angle, the one opposite the given side. It will be ...

B = 180° -A -C = 180° -109° -13° = 58°

Using this information and the Law of Sines, you can find the remaining sides.

a/sin(A) = b/sin(B) = c/sin(C)

Then the missing sides are ...

a = b(sin(A)/sin(B)) = 6(sin(109°)/sin(58°)) ≈ 6.6896

c = b(sin(C)/sin(B)) = 6(sin(13°)/sin(58°)) ≈ 1.5915

The missing measures are ...

B = 58°

a = 6.6896

c = 1.5915

7 0

3 years ago

What is the answer to: (1 1 5 ÷( 17 40 0.6−0.005))·1.7 5 6 1 1 3 −1 23 30 4.75 7 1 2 33÷4 5 7 ÷0.25?

ehidna [41]

This is crazy. If I'm reading this right (I'm not sure why there are spaces put in between some of those numbers like there is), I'm getting that the answer is
-1079.242293. But again, those spaces are throwing me off. I eliminated the spaces between the numbers while I was performing the operations in order.

3 0

3 years ago

A box contains 8 two-inch screws. Four have a Phillips head and 4 have a slotted head. In how many ways can 4 screws be chosen s

hammer [34]

Answer:

There are $6\cdot 6=36$ different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

Step-by-step explanation:

If 4 screws must be chosen so that 2 have a Phillips head and 2 have a slotted head, then you have to choose 2 screws with a Phillips head from 4 screws with a Phillips head and 2 screws with a slotted head from 4 screws with a slotted head.

You can choose 2 screws with a Phillips head from 4 screws with a Phillips head in

$C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6$

different ways.

You can choose 2 screws with a slotted head from 4 screws with a slotted head in

$C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6$

different ways.

In total there are $6\cdot 6=36$ different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

7 0

2 years ago