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WINSTONCH [101]
4 years ago
7

If one sound wave has twice the amplitude of another the first sound is​

Physics
1 answer:
nikdorinn [45]4 years ago
5 0

Answer:

occurs when path-length difference is:

Δr=mlambda and m=0,1,2,3...

Explanation:

I think thats the answer.

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Brent made the table shown to discribe two different relationships between animals.
grigory [225]

i think it is the second one due to the preditory descritpion of relationship A


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4 years ago
A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another
laiz [17]

Answer

given,

watermelon blown into three pieces

two pieces of mass m

both pieces speed = v = 31 m/s

mass of third piece = 3 m

using conservation of mass

0 = m V \hat{i} + m V \hat{j} + (3\ m)V_3

V_3 = \dfrac{V}{3}(-\hat{i}-\hat{j})

V_3 = \dfrac{V}{3}\sqrt{1^2+1^2}

V_3 = \dfrac{V}{3}\sqrt{2}

velocity of third component

V_3 = \dfrac{31}{3}\sqrt{2}

V_3 = 14.61\ m/s

angle

\theta = tan^{-1}(\dfrac{-1}{-1})

\theta = tan^{-1}(1)

\theta = 45^0

5 0
4 years ago
Which cannot be separated into simpler substances?
marin [14]

Answer:

An element is a pure substance that cannot be separated into simpler substances by chemical or physical means. There are about 117 elements.

Explanation:

6 0
3 years ago
Read 2 more answers
A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t
vladimir1956 [14]

a) \omega=\frac{-mvR}{I+MR^2}

b) v=\frac{-mvR^2}{I+MR^2}

Explanation:

a)

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

L_1=0

Later, after the girl throws the rock, the angular momentum will be:

L_2=(I_M+I_g)\omega +L_r

where:

I is the moment of inertia of the merry-go-round

I_g=MR^2 is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

\omega is the angular speed of the merry-go-round and the girl

L_r=mvR is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

L_1=L_2

So we find:

0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

b)

The linear speed of a body in rotational motion is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

\omega=\frac{-mvR}{I+MR^2} is the angular speed

r=R is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

v=\omega R=\frac{-mvR^2}{I+MR^2}

5 0
3 years ago
Please help on this one!!
inysia [295]

The energy transformations that occur as you coast down long hill on a bicycle, including the brakes to make the bike stop at the bottom, is that at the top of the hill you have high GPE AND LOW KE, on your way down you have HIGH KE AND LOW GPE, and at the bottom you have thermal energy due to the stop of the brakes.

the law of conversation of energy and describe the energy transformations that occur as you coast down a long hill on a bicycle and then apply the brakes to make the bike stop at the bottom.


3 0
3 years ago
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