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devlian [24]
3 years ago
12

If there is 30 grams of O2 how many grams of CO2 can it make

Chemistry
1 answer:
igomit [66]3 years ago
7 0

Explanation:

hope it helps you with the question

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How can you make an unsaturated solution from a saturated solution?
riadik2000 [5.3K]

Answer:

By heating the solution a saturated solution can be changed into an unsaturated solution. Without adding any solvent it can be changed into an unsaturated solution. Example: on heating a saturated solution of sugar in high temperature, it starts dissolving.

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2 years ago
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3 years ago
How many grams of hydrogen are contained in 2.00 mol of C6H7N
Setler [38]

Answer:- 14.0 moles of hydrogen present in 2.00 moles of [tex]C_6H_7N .

Solution:- We have been given with 2.00 moles of C_6H_7N and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:

2.00molC_6H_7N(\frac{7molH}{1molC_6H_7N})(\frac{1.0gH}{1molH})

= 14.0 g H

So, there are 14.0 g of hydrogen in 2.00 moles of  C_6H_7N .

3 0
3 years ago
How many neutrons does element X have if its atomic number is 30 and its mass number is 70?
Yanka [14]
The answer is 40.

We can solve this by finding out the number of protons, and neutrons. Atomic number of an element means the number of protons in that element. So, the atom has 30 protons if the atomic number is 30.

On the other hand, mass number is the total number of protons and neutrons, but not electrons, because they're too light comparing to the other 2. Therefore, we can simply solve the number of neutrons in the atom by subtracting the number of protons from the mass number. 70 - 30 = 40.

Therfore, the number of neutrons is 40.
3 0
3 years ago
What is GMOs? ( Thanks btw )​
Sunny_sXe [5.5K]

Answer:

living organisms whose genetic material has been artificially manipulated in a laboratory through genetic engineering

Explanation:

5 0
3 years ago
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