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algol13
3 years ago
13

scrieti in caiete substantivele ,adjectivele sau verbele apartinand familiei lexicale a urmatoarelor cuvinte din text : inima,ar

ipa,piatra,umbra,nor,dragoste
Physics
1 answer:
ser-zykov [4K]3 years ago
5 0
Yes the answer is yes, all the way yes
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Two objects gravitationally attract with a force of 100 N. If the mass of one object is doubled and the mass of the other object
barxatty [35]

Hello!

Recall the equation for gravitational force:
F_g = \frac{Gm_1m_2}{r^2}

Fg = Force of gravity (N)
G = Gravitational constant

m1, m2 = masses of objects (kg)
r = distance between the objects' center of masses (m)

There is a DIRECT relationship between mass and gravitational force.

We are given:
F_g = 100N

If we were to double one mass and triple another, according to the equation:
F'_g = \frac{G(2m_1)(3m_2)}{r^2} = 6(\frac{G(m_1)(m_2)}{r^2}) = 6F_g

Thus:
6 * F_g = 6 * 100 = \boxed{600N}

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2 years ago
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IRINA_888 [86]
Illegal immigrants. Yep
8 0
3 years ago
Metal sphere A is hung from the ceiling by a long, thin string and given a positive charge. An identical sphere B is suspended n
IrinaK [193]

Answer:

A decreases while B increases because the equilebrium only reacts to different sphers of this substance.

Explanation:

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3 years ago
Describe motion of the sun
Olenka [21]

Answer:

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A baseball of radius r = 5.2 cm is at room temperature T = 20.8 C. The baseball has emissivity of ε = 0.86 and the Stefan-Boltzm
Marrrta [24]

Answer:

P = 12.37 \frac{J}{s} = 12.37 Watts

Explanation:

Previous concepts

The Thermal radiation is one of "3 mechanisms who allows to bodies exchange energy".

The thermal radiation formula is given by:

\frac{P}{A} = \epsilon \sigma T^4

Where \sigma = 5.67 x10^{-8} \frac{J}{sm^2 K^4}

If we solve for P we got:

P = A \epsilon \sigma T^4

Since we have a baseball ball considered as a sphere the superficial area is given by:

A = 4\pi r^2

Solution to the problem

And if we replace this into our equation of P we got:

P = (4\pi r^2) \epsilon \sigma T^4

And we can reorder this like that:

P = 4 \epsilon \pi \sigma r^2 T^4

We can convert the radius to meters and we got:

r= 5.2 cm*\frac{1m}{100 cm}=0.052 m

Now we can convert the temperature to Kelvin and we got:

T = 20.8 +273.15 = 293.95 K

\epsilon = 0.86 the emissivity given

And now we can replace into the formula for P and we got:

P = 4*0.86*\pi *(5.67x10^{-8} \frac{J}{s m^2 K^4}) (0.052m)^2 (293.95 K)^4

P = 12.37 \frac{J}{s} = 12.37 Watts

6 0
3 years ago
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