Answer:
mass O2 = 222.5 g
Explanation:
- %wt = ((mass compound)/(mass sln))×100
balance reaction:
∴ %wt H2 = 11 % = ((mass H2)/(mass H2O))×100
∴ %wt O2 = 89 % = ((mass O2)/(mass H2O))×100
∴ mass H2O 250 g
⇒ mass O2 = (0.89)(250 g)
⇒ mass O2 = 222.5 g
Answer is: 116,1 g of Li₃N.
Chemical reaction: Li₃N + 3H₂O → 3LiOH + NH₃.
m(LiOH) = 240g.
n(LiOH) = m(LiOH) ÷ M(LiOH).
n(LiOH) = 240 g ÷ 24 g/mol = 10 mol.
from chemical reaction: n(LiOH) : n(Li₃N) = 3 : 1.
10 mol : n(Li₃N) = 3 : 1.
n(Li₃N) = 3,33 mol.
m(Li₃N) = n(Li₃N) · M(Li₃N)
m(Li₃N) = 3,33 mol · 34,85 g/mol = 116,1 g.
Answer:
The values associated with the term, standard state, in a thermochemical system are option c
Explanation:
Temperature: 0.00 °C; pressure: 1.000 standard atmosphere
Otherwise you can write 0°C as 273 K
1 atm as 1.01325 bar, or 1013 mbars
