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Alex
3 years ago
15

The amount of force exerted on an object due to gravity. true or false

Physics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

True

Explanation:

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Water, in a 100-mm-diameter jet with speed of 30 m/s to the right, is deflected by a cone that moves to the left at 14 m/s. Dete
podryga [215]

Answer:

Explanation:

The velocity at the inlet and exit of the control volume are same V_i=V_e=V

Calculate the inlet and exit velocity of water jet

V=V_j+V_e\\\\V=30+14\\\\V=44m/s

The conservation of mass equation of steady flow

\sum ^e_i\bar V. \bar A=0\\\\(-V_iA_i+V_eA_e)=0

A_i\ \texttt {is the inlet area of the jet}

A_e\ \texttt {is the exit area of the jet}

since inlet and exit velocity of water jet are equal so the inlet and exit cross section area of the jet is equal

The expression for thickness of the jet

A_i=A_e\\\\\frac{\pi}{4} D_j^2=2\pi Rt\\\\t=\frac{D^2_j}{8R}

R is the radius

t is the thickness of the jet

D_j is the diameter of the inlet jet

t=\frac{(100\times10^{-3})^2}{8(230\times10^{-3}} \\\\=5.434mm

(b)

R-x=\rho(AV_r)[-(V_i)+(V_c)\cos 60^o]\\\\=\rho(V_j+V_c)A[-(V_i+V_c)+(V_i+V_c)\cos 60^o]\\\\=\rho(V_j+V_c)(\frac{\pi}{4}D_j^2 )[V_i+V_c](\cos60^o-1)]

1000kg/m^3=\rho\\\\44m/s=(V_j+V+c)\\\\100\times10^{-3}m=D_j

R_x=[1000\times(44)\frac{\pi}{4} (10\times10^{-3})^2[(44)(\cos60^o-1)]]\\\\=-7603N

The negative sign indicate that the direction of the force will be in opposite direction of our assumption

Therefore, the horizontal force is -7603N

7 0
3 years ago
You throw a stone upward from the top of a building at an angle of 25° to the horizontal and with an initial speed of 15 m/s. I
Alex787 [66]

Answer:

11.025 m

87.75 m

Explanation:

Time of flight(T) of a projectile = 2U(sin∅)/g

Where U = initial Velocity, g = acceleration due to gravity, ∅= angle of projection.

Make ∅ the subject of the the equation,

∅ = sin⁻¹[(T× g)/2U]

Where U = 15m/s, T= 3.0 s, g = 9.8 m/s²

∅ = sin⁻¹[(3 × 9.8)/(2×15)]

∅ = sin⁻¹(29.4/30)

∅= sin⁻¹(0.98) = 78.52°

Using the formula for maximum height of a projectile

H = U²sin²∅/2g

H = 15²(sin²78.52)/2 × 9.8

H = 225(0.98 × 0.98)/19.6

H = 216.09/19.6

H = 11.025 m

Range (R) = U²sin2∅/g

R = 15²sin(2×79.52)/9.8

R = 225(0.39)

R =87.75 m

∵ the building is = 11.025 m tall and the base of the building is 87.75m away from where the stone landed.

6 0
3 years ago
What are the four main reasons as to why, despite having an abundance of minerals and natural resources, Pakistan has been unabl
Andre45 [30]

Answer:

GDP growth rate is low

Political instability

Lack of technical skills due to low literacy rate

Pressure from neighboring countries

Explanation:

Gross Domestic Product growth rate of Pakistan is much lower than many developed countries. The GDP growth rate for Pakistan is nearly 5% which is not even stable and it variate from plans. Due to which Pakistan is unable to use its available resources to the fullest. Also one of major issue is political instability in the country. After the loss of great leader Quaid e Azam Pakistan has not faced any loyal leader till date.

Noise pollution, health issues, lack of provision of basic necessities to many are few other factors which give rise to poor law and order situation in the country. Lack of availability of heavy machinery and poor infrastructure has contributed to the country decline. There is abundance of natural resources in the country but due to these issues the country is unable to deal with the challenges.

The pressures from neighboring countries have made the situation even worst. The heavy loan burden is restricting the country from development. The covenants imposed by the lenders have limited the country's ability to use its natural resources and become stable.

5 0
3 years ago
What is the mass of a crane that has a weight of 697,005.40N?
igomit [66]

Explanation:

hope this helps you out if not im sorry

6 0
2 years ago
You are an industrial engineer with a shipping company. As part of the package- handling system, a small box with mass 1.60 kg i
wlad13 [49]

Answer:

a) V = 0.82m/s

b) Vmax = 0.985 m/s

Explanation:

By conservation of energy we know that:

Eo = Ef    \frac{m*V^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*Xmax

Solving for V we get:

V = 0.82 m/s

To find the maximum speed we will do the same to an intermediate point where the compression is X and the distance for the work donde by frictions is given by (Xmax - X) = (0.28m - X):

\frac{m*Vmax^{2}}{2}+\frac{K*X^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*(Xmax-X)

Then we have to solve for V, derive and equal zero in order to find position X. After solving the derivative we get:

X = 0.1m    Replacing this value into the equation for Vmax:

Vmax = 0.985m/s

6 0
3 years ago
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