Answer:
The augmented matrix for the system of equations is ![\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%262%26-3%261%5C%5C7%260%265%268%5C%5C4%261%26-3%266%5Cend%7Barray%7D%5Cright%5D)
.
Step-by-step explanation:
This system consists in three equations with three variables (
, 
, 
).The augmented matrix of a system of equations is formed by the coefficients and constants of the system of linear equations. In this case, we conclude that the system of equations has the following matrix:
The augmented matrix for the system of equations is .
Answer: Equilateral triangles are also right triangles sometimes. All angles of an equilateral are congruet sometimes.
19/100
24/100
845/100= 8 45/100
3/4
Answer:
B
Step-by-step explanation:
First, check to see which graph has a line going through the point (2,3). B and D are the only ones that have lines going through (2,3) (A comes close but it is not quite).
Next, you need to see which line would be parallel to the equation 3x-y=2. When two lines are parallel, they have the same slope. You have to turn that equation into point-slope formula (y=mx+b with m being the slope and b being the y-intercept). First, subtract 3x from both sides. You will then get -y=-3x+2. Then y needs to be alone (right now it has a -1 attached). Divide both sides by -1 to get y=3x-2. The number in front of the x is the slope, in this case, 3 or 3/1 (we do not care about the y-intercept, it will not help us in this problem since we are looking for a line parallel to this equation and so our line will not have the same y-intercept as this other equation). Since the line in parallel to that equation, we know that this line also has a slope of 3/1. Find the line between B and D that has a slope of 3/1, you get B (the line goes up 3 over 1).
