The unit of the quotient of inductance and resistance is called the time constant.
what is time constant?
The time constant τ (tau),is measured by T=L/R,in seconds,where R is the value of resistor in ohms and L is the value of inductor in Henry.
When a current is applied to an inductor it takes some time for the current to reach its maximum value, after which it will remain in a "steady state" until some other event causes the input to change. The time taken for the current to rise to its steady state value in an LR circuit depends on:
The resistance (R)
This is the total circuit resistance, which includes the DC resistance of the inductor (RL) itself, plus any external circuit resistance.
The inductance (L)
Which is proportional to the square of the number of turns, the cross sectional area of coil and the permeability of the core.
The transient time of any inductive circuit is determined by the relationship between the inductance and the resistance. For example, for a fixed value resistance the larger the inductance the slower will be the transient time and therefore a longer time constant for the LR series circuit. Likewise, for a fixed value inductance the smaller the resistance value the longer the transient time.
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A. The laws of thermodynamics
elasticity stretches and can also return to it's normal size ..
Answer:
The 43kg student will be sliding at 1.79m/s opposite the direction the 34kg student is going.
Explanation:
Conservation of linear momentum!
The law of conservation of momentum says that in an isolated system, the momentum before must equal the momentum after:
.
For our two students
(notice the - sign in -2.4m/s, this means going to the left)
since the students were not moving at first, , therefore we have
solving for gives
Hence the 43kg student will be sliding at 1.79m/s to the right.
Answer:
a) 2.53 * 10^-2 m/s
b) -4.78 * 10^-2 m/s
c) 1.21 * 10^-1 m/s
Explanation:
Given data :
Mass of block = 10 kg
Measuring 250mm on each side
a) calculate the speed when a force of 75N is applied to pull block upwards
F = f + W sin∅ ( equation for applying the force of equilibrium condition in the x axis ) ----- ( 1 )
f ( friction force )= ( 16400v * 6.25 *10^-2) = 1025 v
F ( force applied ) = 75
W ( weight of block ) = 10 * 9.81 = 98.1 N
∅ = 30°
input values into equation 1
V = = 2.53 * 10^-2 m/s
b) Speed when no force is applied on the block
F = f + W sin∅
F = 0
f = 1025 V
W = 98.1 N
∅ = 30°
hence V = = - 4.78 * 10^-2 m/s
c) when a force is applied to push block down the incline
F = f + W sin∅ ----- ( 3 )
F = 75 N
f = 1025 V
W = 98.1 N
∅ = 30°
input values into equation 3 considering the fact that the weight of the block is acting in the opposite direction
75 = 1025 V - 98.1 ( sin 30° )
V = = 1.21 * 10^-1 m/s