Question

An electrical heater is used to supply 245.0 J of energy to a 15.0 g sample of aluminum, originally at 310.0 K. Determine the final temperature in degrees Kelvin. (the specific heat capacity for aluminum is 24.35 Jmol-1K-1)

Answer 1

Answer:

$T_f=328.1 K$

Explanation:

To determine the final temperature of the sample, we use the specific heat formular as follows:

$Q=mCp(T_f-T_0)\\T_f=\frac{Q}{mCp} +T_{0}\\mol Al= \frac{15g}{26.98gmol^{-1}}=0.555 mol\\T_f=\frac{245.0J}{0.555mol\times24.35Jmol^{-1}K^{-1}} +310.0K\\T_f=328.1 K$

Finally, the temperature of the aluminium sample has raised 18 K.