Convert the following as instructed:

The magnitude of the magnetic field at point P for a certain electromagnetic wave is 2.12 μT. What is the magnitude of the elect

valkas [14]

Answer:

The electric field is $E = 636 \ V/m$

Explanation:

From the question we are told that

The magnitude of magnetic field is $B = 2.12 \mu T = 2.12*10^{-6} \ T$

The value for speed of light is $c = 3.0 *10^8 \ m/s$

Generally the magnitude of the electric field at point P is

$E = B * c$

substituting values

$E = 2.12 *10^{-6} * 3.0 *10^{8}$

$E = 636 \ V/m$

8 0

3 years ago

How do I find final velocity

svp [43]

The formula for final velocity is Speed= distance/time (s=d/t)
Velocity is another word for speed.

7 0

3 years ago

Worth 30 points! PLEASE ANSWER ASAP!!!

Juli2301 [7.4K]

V: there would be no seasons and humanity would suffer

7 0

3 years ago

Two sound waves, from two different sources with the same frequency of 420 Hz travel in the same direction at 336 m/s. The sourc

Tresset [83]

Answer:

Pi(3.14) radians or 180º degrees

Explanation:

First of all, we need to obtain the wavelength of a wave traveling to the speed of sound and 420 Hz of frequency.

The formula is:

$l=wavevelocity/frequency$

where l = wavelength in meters

With current values:

l = 336 [m/s]/420[1/s] = 0.8 meters

Since a complete cycle (360º or 2pi radians) needs 0.8 meters to complete, 0.4 meters or 40 cm is just half of it, making a 180º degree phase or 3.14 radians.

8 0

3 years ago

What length of a certain metal wire of diameter 0.15 mm is needed for the wire to have a resistance of 15 ω? the resistivity of

Murljashka [212]

The resistance of the cylindrical wire is $R=\frac{\rho l}{A}$ .

Here $R$ is the resistance, $l$ is the length of the wire and $A$ is the area of cross section. Since the wire is cylindrical $A=\frac{\pi d^2}{4}$ . Rearranging the above equation,