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mixer [17]
2 years ago
10

Convert the following as instructed:

Physics
1 answer:
Elis [28]2 years ago
7 0
3.4m
6700g
172800s
1 day
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What's something that I've done in my life that is related to physics
Allisa [31]

That's a very difficult question to answer, because you give us
no information regarding what you have done in your life. 

We can only assume that you have most likely breathed on occasion,
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summer storm, taken a trip in an airplane, and waited for a cup of
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is greatly enhanced when you understand some of the Physics involved.

6 0
2 years ago
Which element of a valid contract is established by getting the signatures of all parties?
sweet [91]

The element of a valid contract which is established by getting the signatures of all parties is <u>mutual agreement</u>

<h3>What is an element of a valid contract?</h3>

An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

Some elements of valid contract are:

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8 0
1 year ago
A radio station's channel, such as 100.7 fm or 92.3 fm, is actually its frequency in megahertz (mhz), where 1mhz=106hz. calculat
lakkis [162]
When it comes to wave behavior, there are parameters called wavelength and frequency. These two are related by speed of the radiowave. Radiowaves are electromagnetic waves which travels as fast as light. The wavelength is the distance while frequency is the reciprocal of time. When you multiply them both, you get the electromagnetic wave's speed. The equation is c = wavelength*frequency, where c is the speed of light equal to 3 x 10^8 m/s. 

3 x10^8 m/s = wavelength/104.9 x 10^6 Hz   (Hertz is 1/s)
wavelength = 2.86 meters
6 0
3 years ago
amping equipment weighing 6.0 kN is pulled across a frozen lake by means of ahorizontal rope. The coecient of kinetic friction i
Harman [31]

Answer:

Work done = 422.45 kJ

Explanation:

given,                                  

weight of equipment = 6 kN      

coefficient of kinetic friction = 0.05          

distance up to which it is pulled = 1000 m

constant acceleration = 0.2 m/s²                    

Work done by the camper = ?                

actual acceleration acting a'      

m a = m a' - μ mg            

a' = a + μ g                      

a' = 0.2 + 0.05 x 9.8                

a' = 0.69 m/s²                              

Work done = Force x distance

F = m a'                                                            

F = \dfrac{6000}{9.8} \times 0.69

F = 422.44897 N                            

Work done = F x d                          

Work done = 422.44897 x 1000

Work done = 422449 J                  

Work done = 422.45 kJ            

4 0
2 years ago
A scientist makes a device to catch baseballs. A long bar of total mass 2.2kg and length 1.2m is fixed at its center. It catches
Valentin [98]

Answer:

ωf = 4.53 rad/s

Explanation:

By conservation of the angular momentum:

Ib*ωb = (Ib + Ic)*ωf

Where

Ib is the inertia of the ball

ωb is the initial angular velocity of the ball

Ic is the inertia of the catcher

ωf is the final angular velocity of the system

We need to calculate first Ib, Ic, ωb:

Ib = mb*(L/2)^2=0.15*(1.2/2)^2=0.054 kg.m^2

Ic = mc/12*L^2=2.2/12*1.2^2=0.264 kg.m^2

ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s

Now, ωf will be:

\omega f = \frac{Ib*\omega b}{Ib + Ic}  = 4.53rad/s

8 0
2 years ago
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