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mixer [17]
2 years ago
10

Convert the following as instructed:

Physics
1 answer:
Elis [28]2 years ago
7 0
3.4m
6700g
172800s
1 day
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A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit
likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density \mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 120=753.6rad/sec

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt

From the relation we can see that power P\ \propto\ A^2

So if amplitude is halved then power will be \frac{1}{4} times

So power will be equal to \frac{0.2023}{2}=0.0505watt

4 0
3 years ago
Guys answer with a clear explanation and plzz don't spam.
timama [110]

Answer:

20.7N

Explanation:

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So there are a wats up group where you can get help step by step and well explained by the trusted experts.

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3 0
3 years ago
Concept Simulation 2.3 offers a useful review of the concepts central to this problem. An astronaut on a distant planet wants to
Alexandra [31]

Answer:

1.40 m/s^2

Explanation:

Given data

Velocity= 17.4 m/s

time= 12.4 seconds

We want to find the acceleration of the rock

We know that

acceleration = velocity/time

Substitute

acceleration= 17.4/12.4

acceleration=1.40 m/s^2

Hence the acceleration is 1.40 m/s^2

7 0
2 years ago
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
lukranit [14]

Answer:(a) 2.40 (b) horizontal distance. (c) 0.630. (d) 6.50

Explanation:that's all is talking about a speed and distance and time right

3 0
3 years ago
15. Find the speed of a disc of radius 0.5 meters and mass 2-kg at the base of the incline. The disc starts at rest and rolls do
mote1985 [20]

Explanation:

sorry_______________

7 0
3 years ago
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