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Wittaler [7]
3 years ago
10

A hot cup of coffee (treat it like water) rests on a windowsill. If it cools off from 90 C

Chemistry
2 answers:
zavuch27 [327]3 years ago
6 0

Answer:

823.84~mL

Explanation:

We have to use the <u>heat equation</u> for this problem:

Q~=~m*Cp~*ΔT

Where:

Q=heat=103310 J

m = mass = <u>Unknow</u>

Cp=specific heat (of water)=4.18 \frac{J}{g^{\circ}C}

ΔT= 30 ºC

Now, we have to <u>solve for "m"</u>:

m=\frac{Q}{Cp*deltaT}=\frac{103310~J}{4.18\frac{J}{g^{\circ}C}*30^{\circ}C}=823.84~g

Finally, we have to <u>convert</u> from grams to mL using the <u>density</u> value 1~\frac{g}{mL}.

823.84~g~\frac{1~mL}{1~g}=823.84~mL

kakasveta [241]3 years ago
5 0

Answer:

1721.8ml

Explanation:

90-30=60

103,310÷60=1721.83333333

1721.83333333= 1721.8

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