Question

A hot cup of coffee (treat it like water) rests on a windowsill. If it cools off from 90 C

Answer 1

Answer:

$823.84~mL$

Explanation:

We have to use the heat equation for this problem:

$Q~=~m*Cp~*$ΔT

Where:

Q=heat=103310 J

m = mass = Unknow

Cp=specific heat (of water)=4.18 $\frac{J}{g^{\circ}C}$

ΔT= 30 ºC

Now, we have to solve for "m":

$m=\frac{Q}{Cp*deltaT}=\frac{103310~J}{4.18\frac{J}{g^{\circ}C}*30^{\circ}C}=823.84~g$

Finally, we have to convert from grams to mL using the density value $1~\frac{g}{mL}$.

$823.84~g~\frac{1~mL}{1~g}=823.84~mL$

Answer 2

Answer:

1721.8ml

Explanation:

90-30=60

103,310÷60=1721.83333333

1721.83333333= 1721.8