Answer: d. they are a form of reserve fuel storage
Explanation:
Triglycerides are special type of lipids. They are formed by glycerol with three fatty acid chains. The fatty acid chains can vary in length, they can be saturated or unsaturated with varying composition. It is the most abundant lipid in diet. It is available in plant as well as animal based foods. In case of mammals the triglycerides are stored in the adipose tissue in which they are broken to release energy.
The equilibrium constant of the reaction is 1.21 * 10^6 while the change in free energy is -34.7 kJ.
<h3>What is equilirium constant?</h3>
The equilibrium constant shows the extent of conversion of reactants to products.
Now we know from the Nernst equation that;
Ecell = E°cell - 0.0592/n logQ
E°cell = 0.52−0.16=0.36 V
Since Ecell = 0 V at equilibrium,
0 = 0.36 - 0.0592/1 log K
0.36 = 0.0592/1 log K
log K = 0.36/ 0.0592
K = antiog (0.36/ 0.0592)
K = 1.21 * 10^6
ΔG = -RT lnK
ΔG =-(8.314 * 298 * ln1.21 * 10^6)
ΔG =-34.7 kJ
Learn more about equilibrium constant:brainly.com/question/10038290
Answer:
high electrical and thermal conductivity
Why don’t you just use google?
<h2>
Question
</h2>
A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure
<h2>
Answer:</h2>
434.32mL
<h2>
Explanation:</h2>
Using the combined gas law:
= k
Where;
P = Pressure
V = Volume
T = Temperature
k = constant.
It can be deduced that:
= 
= k ---------------------(i)
Where:
P₁ and P₂ are the initial and final pressures of the given gas
V₁ and V₂ are the initial and final volumes of the given gas
T₁ and T₂ are the initial and final temperatures of the gas.
<em>From the question:</em>
the gas is methane
P₁ = 760mmHg
P₂ = 616mmHg
V₁ = 398mL
V₂ = ?
T₁ = 30°C = (30 +273)K = 303K
T₂ = -5°C = (-5 +273)K = 268K
Substitute these values into equation (i) as follows;
= 
Solve for V₂
V₂ = 
V₂ = 434.32mL
Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL
