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3 years ago

PLEASE HELP ASAP

Physics

1 answer:

77julia77 [94]3 years ago

8 0

Answer:

<em>The first choice (32m/s) is the closest to the answer</em>

Explanation:

The magnitude of a vector is the distance between the initial and the end point of the vector.

Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:

$\mid \vec{V} \mid =\sqrt{V_x^2+V_y^2}$

The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.

Calculate the magnitude of the velocity:

$\mid \vec{V} \mid =\sqrt{28^2+15^2}$

$\mid \vec{V} \mid =\sqrt{784+225}$

$\mid \vec{V} \mid =\sqrt{1009}$

$\mid \vec{V} \mid =31.8 \ m/s$

The first choice (32m/s) is the closest to the answer

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